Oxygen decays to form nitrogen. 15 8 O → 15 7 N + 0 1 e This type of nuclear decay is called
1 answer:
The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.
<h3>What is a beta plus decay?</h3>A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.
In the given equation below:
Oxygen decays to form nitrogen due to a decrease in atomic number.
This is an example of beta plus decay.
In conclusion, oxygen decays to form nitrogen beta plus decay.
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<u>Answer:</u> The theoretical yield of solid lead comes out to be 5.408 grams.
<u>Explanation:</u>
To calculate the moles, we use the following equation:
- <u>Moles of Lead nitrate:</u>
Given mass of lead nitrate = 8.65 grams
Molar mass of lead nitrate = 331.2 g/mol
Putting values in above equation, we get:
- <u>Moles of Aluminium:</u>
Given mass of aluminium = 2.5 grams
Molar mass of aluminium = 27 g/mol
Putting values in above equation, we get:
For the given chemical reaction, the equation follows:
By Stoichiometry:
3 moles of lead nitrate reacts with 2 moles of aluminium
So, 0.0261 moles of lead nitrate are produced by = of aluminium.
As, the required amount of aluminium is less than the given amount. Hence, it is considered as the excess reagent.
Lead nitrate is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 moles of lead nitrate are produces 3 moles of lead metal.
So, 0.0261 moles of lead nitrate will produce = of lead metal.
- Now, to calculate the grams or theoretical yield of lead metal, we put in the mole's equation, we get:
Molar mass of lead = 207.2 g/mol
Putting values in above equation, we get:
Mass of lead = 5.408 grams
Hence, the theoretical yield of solid lead comes out to be 5.408 grams.