Cant see the question clearly
It is not factorable. Factors of 21 are. 21 and 1
7 and 3. None of those add up to 12
Step-by-step explanation:
Apply Quoteint of Powers. Divide the intergers. serpately.
Note that Quotient of Powers is
So the answer is
The answer is
or
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
Answer:
9
Step-by-step explanation:
6a=54
a=54/6
a=9
