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3 years ago

-3x - 5 = 16 (PLEASE HELP ME ASAP I WILL GIVE YOU BRAINLIEST AND PLEASE SHOW YOUR WORK)

Mathematics

1 answer:

deff fn [24]3 years ago

6 0

Start by writing -3x-5=16. You can add 5 to both sides since the inverse operation of negative is adding positive. You will then get 16+5=21. Then you will get -3x=21. Divide by -3 on both sides. -3x/-3. 21/-3=-7 x=-7. Now check your answer -3(-7)=21-5=16. Checks out. Hopefully this helps!

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How do you use equivalent fractions to compare the fractions in each pair

Alenkasestr [34]

Firstly you need to to reduce to a common denominator by multiplYing the whole fraction. This way you have to multiply 4/5 by 2 (both numerator and denominator). so 4/5 = 8/10. And now you have 8/10 and 9/10. You compare only numerators. This way you have 8/10 <9/10. Same goes for 2/3 and 5/8. Only here you need to multiply both fractions. The common denominator here is 24. So you have to multiply 2/3 by 8 and 5/8 by 3. You now have to compare 16/24 and 15/24. 16/24>15/24.

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3 years ago

Write the equation of the line that passes through the points (-6, -9) and

e-lub [12.9K]

Answer:

y - 7 = 16/13(x - 7)

General Formulas and Concepts:

Alg I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate

y₁ - y coordinate

m - slope

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-6, -9)

Point (7, 7)

Step 2: Find slope m

Substitute: $m=\frac{7+9}{7+6}$
Add: $m=\frac{16}{13}$

Step 3: Write equation

y - 7 = 16/13(x - 7)

3 0

3 years ago

A loan of $1200 had $36 in interest. the rate was 6% . what was the length of the loan

levacccp [35]

6 months

Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out

4 0

2 years ago

a) Suppose f"(z) exists on an interval I and f(s) has a zero at three distinct points a < b< c on I. Show there is a pbint

Fynjy0 [20]

Answer:

We can find a root in the average point (a+b+c)/3

Step-By-Step Explanation:

We can use the Rolle Theorem. Since f is two times deribable on both [a,b] and [b,c], then there exists points x in (a,b) and y in (b,c) such that f'(x) = f'(y) = 0. Now, again by using Rolle Theorem, since f' is derivable in [x,y] (because it is a closed interval in I), then there exists s in [x,y] such that f''(s) = 0. This proves a.

The cube (x-a)(x-b)(x-c) has 3 roots, a, b and c and it is two times derivable because it is a polynomial. Hence we can use (a) to ensure that there is a root on I. Nevertheless, we can try to find the root manually:

f'(x) = (x-b)(x-c)+(x-a)(x-c)+(x-a)(x-b)

f''(x) = (x-c)+(x-b)+(x-c)+(x-a)+(x-b)+(x-a) = 2(x-a)+2(x-b)+2(x-c) = 2( (x-a) + (x-b) + (x-c) ) = 6x - 2 (a+b+c).

We want x such that

6x - 2(a+b+c) = 0, or, equivalently,

3x - (a+b+c) = 0

Hence

x = (a+b+c)/3

Is a root of f'' in I.

3 0

3 years ago

Consider the quadrilateral ABCD. Which information could be used to prove that the quadrilateral ABCD is a parallelogram?

statuscvo [17]

Answer:

A and Care parallel, B and D are parallel

Step-by-step explanation:

4 0

3 years ago