Which of the following is a foci of x^2/16-y^2/4=1
1 answer:
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Answer:
Option C
Step-by-step explanation:
According to the graph, there are vertical asymptotes at and
. Therefore, C is correct because -3+3=0 and 7-7=0.
For this case we have the following polynomial:
To answer the question, what we must do is rewrite the polynomial in its standard form.
We have then that the polynomial will be given by:
Therefore, we have the ordered polynomial in descending form of exponents.
Therefore, the second term of the polynomial is:
Answer:
The second term of the polynomial is given by: