Answer:
Step-by-step explanation:
From the given picture,
∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]
m∠ECA = m∠BFD [Given]
m∠ECA + m∠ACB = 180° [Liner pair of angles]
m∠BFD + m∠DFE = 180° [Liner pair of angles]
m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]
m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]
Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]
Answer:
Yes, we reject the auto maker's claim.
Step-by-step explanation:
H0 : μ ≥ 20
H1 : μ < 20
Sample mean, xbar = 18 ;
Sample size, n = 36
Standard deviation, s = 5
At α = 0.01
The test statistic :
(xbar - μ) ÷ s /sqrt(n)
(18 - 20) ÷ 5/sqrt(36)
-2 /0.8333333
= - 2.4
Pvalue from test statistic : Pvalue = 0.00819
Pvalue < α
0.00819 < 0.01
Hence, we reject the Null
2 because I looked it up on google
That is called the Origin , where the number 0 is.
Answer:
-6,0 & -3,0
Step-by-step explanation:
