Let m and r represent the maximum speeds of Malcolm and Ravi in km/h, respectively.
... (m + r)/2 = 260 . . . . . the average of their speeds was 260 kph
... 2m = r + 80 . . . . . . . . double Malcolm's speed is 80 kph more than Ravi's
The second equation can be solved for r and that expression substituted into the first equation.
... 2m - 80 = r . . . . . . . . . . . an expression for r from the second equation
... (m + 2m - 80)/2 = 260 . . . the result of substituting that into the first
... 3m - 80 = 520 . . . . . . . . multiply by 2
... m = 200 . . . . . . . . . . . . . add 80 and divide by 3
... 2·200 - 80 = r = 320 . . .substitute the value of m into the expression for r
Malcolm's maximum speed was 200 km/h.
Ravi's maximum speed was 320 km/h.
Answer: Read Sol.
Step-by-step explanation: To solve these, call each given zero = z. The function is when given a zero that is an integer (x-z1)(x-z2)(x-z3)... so on until all zeroes are used. This works for fractions also. But when you have irrationals, you will have to make sure each irrational solutions conjugate is there. So if a given zero is 2-sqrt3, then always 2+sqrt3 will also be a 0. Likewise, if given -4-sqrt7, then -4+sqrt7 will also always be a zero. Use this logic to solve them very quickly! I hope this helps!
The answer should be 21.6
Answer:
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