Answer:
the point is (3, 3) . . . . . . y = 3
Step-by-step explanation:
Write the point-slope equation of the line through the point you know. Then evaluate that equation for x=3 to see what the value of y is.
Point-slope form:
y = m(x -h) +k . . . . slope m through point (h, k)
y = -1/2(x -9) +0 . . . . line with slope -1/2 through point (9, 0)
For x=3, the value of y is ...
y = -1/2(3 -9) + 0 = -1/2(-6) = 3
The value of y is 3.
Answer:
x=72.6
Step-by-step explanation:
use inverse trig because your finding a missing angle. use tan because you haved opp/adj
tan-1=(16/5)
x=tan-1(16/5)
*use a calculator
x=72.6
Answer:

Step-by-step explanation:
<u>Slope-intercept </u><u>form</u>
y= mx +c, where m is the slope and c is the y-intercept
Line p: y= -8x +6
slope= -8
The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.
m(-8)= -1
m= -1 ÷(-8)
m= ⅛
Substitute m= ⅛ into the equation:
y= ⅛x +c
To find the value of c, substitute a pair of coordinates that the line passes through into the equation.
When x= 2, y= -2,
-2= ⅛(2) +c



Thus, the equation of line q is
.
we have

Solve for c--------> that means that clear variable c
so
Divide by
both sides

Adds
both sides

Multiply by
both sides
![a[(R/5)+0.3]=c](https://tex.z-dn.net/?f=a%5B%28R%2F5%29%2B0.3%5D%3Dc)
so
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)
therefore
<u>the answer is</u>
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)