Can someone help me with this one

Daniel [21]

X=90 which (180-90) is 90 for m and n

4 0

3 years ago

At a local store, Kelly and Martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin

grandymaker [24]

Answer:

9.17

Step-by-step explanation:

6 0

3 years ago

HELPPP!!!!!!

Furkat [3]

<h3>Answer: Choice D) 31.2 miles</h3>

This value is approximate.

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Explanation:

Let's focus on the 48 degree angle. This angle combines with angle ABC to form a 90 degree angle. This means angle ABC is 90-48 = 42 degrees. Or in short we can say angle B = 42 when focusing on triangle ABC.

Now let's move to the 17 degree angle. Add on the 90 degree angle and we can see that angle CAB, aka angle A, is 17+90 = 107 degrees.

Based on those two interior angles, angle C must be...

A+B+C = 180

107+42+C = 180

149+C = 180

C = 180-149

C = 31

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To sum things up so far, we have these known properties of triangle ABC

angle A = 107 degrees
side c = side AB = 24 miles
angle B = 42 degrees
angle C = 31 degrees

Let's use the law of sines to find side b, which is opposite angle B. This will find the length of side AC (which is the distance from the storm to station A).

b/sin(B) = c/sin(C)

b/sin(42) = 24/sin(31)

b = sin(42)*24/sin(31)

b = 31.1804803080182 which is approximate

b = 31.2 miles is the distance from the storm to station A

Make sure your calculator is in degree mode.

8 0

3 years ago

Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!

Nataliya [291]

Answer:

Perimeter = 22*sqrt(2)
Area = 60.5 inches
D

Step-by-step explanation:

Remark

You need 2 facts.

A square has 4 equal sides.
It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

a^2 + a^2 = c^2
2a^2 = c^2

Givens

c = 11

Solution

2a^2 = 11^2
2a^2 = 121 Divide by 2
a^2 = 121/2 Take the square root of both sides
sqrt(a^2) = sqr(121/2)
a = 11/sqrt(2) Rationalize the denominator
a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

P = 4*11*sqrt(2)/2
P = 44*sqrt(2)/2
P = 22*sqrt(2)

You don't need the area. The answer is D

Area = s^2
Area = (11*sqrt(2)/2 ) ^2
Area = 121 * 2 / 4
Area = 60.5

8 0

3 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

3 years ago