Answer:
The answer to your question is Volume = 3.30 cm³
Step-by-step explanation:
Data
Volume = ?
height = 14.9 cm
circumference = 2.9 cm
Process
1.- Calculate the radius
circumference = 2πr
-Substitution
2.9 = 2πr
-Solve for r
r = 2.9/2π
r = 1.45/π cm
2) Calculate the volume of the cone
Volume = 1/3πr²h
-Substitution
Volume = 1/3π(1.45/π)²(14.9)
-Simplify
Volume = (1.04)(0.213)(14.9)
Volume = 3.30 cm³
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
Answer: m=5/3
Step-by-step explanation:
i think its right
Answer:
Choice 1
Step-by-step explanation:
m^2 +n^2=13^2
m^2=13^2-n^2
n^2=13^2-m^2
Both m & n =(13 x sq rt 2)/2
To put it another way:
m=(sq rt 2)/2 x 13
n=(sq rt 2)/2 x 13
Answer:
25,49.
Step-by-step explanation: