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dexar [7]
3 years ago
15

Select the correct answer from each drop-down menu.

Biology
1 answer:
attashe74 [19]3 years ago
4 0
I don’t know but it’s hard I keep getting it wrong
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Feeding scrub-jays can lead to starvation of fledgling scrub-jays.
Lilit [14]

The statement “Feeding scrub-jays can lead to starvation of fledgling scrub-jays” is true because if humans feed the birds, they may become reliant on humans and be unable to get their own food, which can lead to starvation and malnutrition

4 0
3 years ago
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Baron Constantin von Economo discovered the involvement of the posterior hypothalamus and the anterior hypothalamus in human ___
Leona [35]

Answer:

Wakefulness and sleep.

Explanation:

Hypothalamus may be defined as the small region of the brain that maintains the homeostasis of the body. The hypothalamus is divided into anterior hypothalamus and posterior hypothalamus.

The anterior hypothalamus of the brain is involved in the sleep activity of the organisms and releases the hormones also. The posterior hypothalamus is involved in the wakefulness of the individual.

Thus, the correct answer is wakefulness and sleep.

3 0
3 years ago
Did T. Rex have hair?
Mazyrski [523]

Answer:

rex was covered in a coat of downy feathers

Explanation:

Some mammals did have hair but T. Rex mostly had feathers

5 0
3 years ago
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Which statement best explains how a tornado might form
ELEN [110]
A tornado is a violently rotating column of air extending from the base of a thunderstorm to the ground, often made visible by a condensation funnel. The formation of tornadoes<span> is complicated. So the answer would be A

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4 0
3 years ago
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Determine the new concentration, in mg/mL, of the starch solution you diluted in the Erlenmeyer flask. Recall from the Procedure
Semmy [17]

Answer:

0.05 mg/mL  ( B )

Explanation:

Given data:

20 mg/ml starch

2% solution = 2g of solute is in 100g of solvent

<u>Determine the new concentration in mg/ml </u>

Dilution equation = C1V1 = C2V2

new concentration ; applying the dilution factor

dilution factor = 1 : 400 ; ( 2 /400 )g = 0.005 g of solute is present in every  100 mL

∴ new concentration = 0.00005 g / 1 mL * ( 1000 mg / 1g ) = 0.05 mg/mL

6 0
3 years ago
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