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1. 408.4 J
The work done by a gas is given by:
where
p is the gas pressure
is the change in volume of the gas
In this problem,
(atmospheric pressure)
is the change in volume
So, the work done is
2. 10170 J
The amount of heat added to the water to completely boil it is equal to the latent heat of vaporization:
where
m is the mass of the water
is the specific latent heat of vaporization
The initial volume of water is
and the water density is
So the water mass is
So, the amount of heat added to the water is
The density is
(180) / (the volume of the lump in cm³) .
The unit of the density is grams/cm³ .
Answer:
-2 m/s²
8.7 m/s
Explanation:
Using Newton's second law, the sum of forces in the x direction:
∑F = ma
-120 N = (60 kg) a
a = -2 m/s²
Given:
Δx = 6.0 m
v₀ = 10 m/s
a = -2 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (10 m/s)² + 2 (-2 m/s²) (6.0 m)
v = 8.7 m/s