Answer:
7.46 J/kg/K
Explanation:
The heat absorbed or lost is:
q = mCΔT
where m is the mass, C is the heat capacity, and ΔT is the change in temperature.
Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:
15.0 J = (0.201 kg) C (10.0 °C)
C = 7.46 J/kg/°C
Which is the same as 7.46 J/kg/K.
<span>Even though the Sun has a greater mass than Earth, the Moon orbits Earth because it's closer to the Earth than to the Sun. Because of this proximity between the Earth and the Moon, the Earth has a stronger gravitational pull than the Sun does. Furthermore, the Earth's mass is 81 times that of the Moon, and so at this proximity, it is more than able to overpower what pull the Sun exerts on the Moon.</span>
Answer:
when a force is applied by one object to a second object, an equal and opposite force is applied back on the first object
Explanation:
Answer:
141.14098 secs
Explanation:
Time taken to see the lightning flash can be gotten from:
Velocity = distance/time
Time = distance/velocity
Time = (47 * 1000)/(3 * 10^8)
Time = 0.0001567 secs
Time taken to hear the thunder can be gotten from:
Velocity = distance/time
Time = distance/velocity
Time = (47 * 1000)/(333)
Time = 141.14114 secs
The time lapse between the lightning flash and the thunder will be:
141.14114 - 0. 0001567
= 141.14098 secs
Explanation:
The acceleration due to gravity g is defined as
and solving for R, we find that
We need the mass M of the planet first and we can do that by noting that the centripetal acceleration 
experienced by the satellite is equal to the gravitational force 
or
The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as
where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as
Solving for <em>M</em>, we get
Putting this expression back into Eqn(1), we get
