A regular hexagon has a side length of 20. Find the area of the hexagon.

Flura [38]

Hello,

Your answer would be 2, -2.

$8x^2 - 4 = 28$

$8x^2-4+4=28+4$

$8x^2 = 32$

$\frac{8x^2}{8}= \frac{32}{8} 
$

$x^2 = 4$

x = +/4

x = 2 or x = -2

2 , -2 would be the answer! :)

Mark Brainliest if this helped you :)

4 0

2 years ago

Read 2 more answers

I need help please this due tomorrow

OLEGan [10]

<em>What do you need help with on your homework. You need all the answers?</em>

<em>My friend. I am a teacher at a middle school</em>

8 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago

Amya spends 2 hours doing her homework. She daydreams about a robot that could do her homework in 10 minutes. If Amya did have t

ryzh [129]

Answer:

t=34.64 mins

Step-by-step explanation:

let Arya be A, Robot be B and Combined time be t

$A+B=\frac{1}{t}\\A=\frac{1}{t+120}\\B=\frac{1}{t+10}\\\frac{1}{t+10}+\frac{1}{t+120}=t\\\frac{1}{t+10}=\frac{t+120-t}{t+120}\\t^2+120t=120t+1200\\t^2=1200\\t=34.6410$

4 0

3 years ago

ok more of a question not like a equation or anything but when do you know when there is a extraneous answer and how do you solv

Likurg_2 [28]

One can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.

<h3>What is an extraneous equation?</h3>

It should be noted that an extraneous equation means a root of a transformed equation that isn't the root of the original equation due to the fact that it's excluded from the domain of the original equation.

In this case, one can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

5 0

1 year ago

A regular hexagon has a side length of 20. Find the area of the hexagon.​

A regular hexagon has a side length of 20. Find the area of the hexagon.