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Reil [10]
3 years ago
14

A regular hexagon has a side length of 20. Find the area of the hexagon.​

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

1039.23 sq units is the answer I believe

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Need help ASAP m<2=92 m<12=74
galben [10]

Answer:

nevermind, i figured it out!

<10 = 92

<8 = 92

<9 = 88

<5 = 106

<11 = 106

<13 = 106

yes these are actually the answers, lol

Step-by-step explanation:

6 0
3 years ago
What the answer here?
Brut [27]

Answer:

x230x

Step-by-step explanation:

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3 years ago
What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

\sqrt{36} =6

BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0
3 years ago
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a football team gains 8 yards on their first play. they lose 12 yards on the next play. what two integers represent the two play
max2010maxim [7]
Negative numbers,8-12=-3
8 0
3 years ago
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In your BIO 111 course, you learn that human hair can vary in diameter, but one estimate of the average diameter is 50 microns o
Dafna11 [192]

Answer:

5000 particles of size 10 nanometer should be stacked

Step-by-step explanation:

Average diameter of the of the human hair = 50 micron = 50 × 10⁻⁶ m

Now,

let the number of 10 nanometer i.e 10 × 10⁻⁹ m particle be 'n'

thus,

n × 10 × 10⁻⁹ m = 50 × 10⁻⁶ m

Therefore to find the number of 10 nanometer i.e 10 × 10⁻⁹ m particle,

n = \frac{50\times10^{-6}}{10\times10^{-9}}

or

n = 5000

Hence,

5000 particles of size 10 nanometer should be stacked

4 0
4 years ago
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