All categories

2 years ago

The given figure is a regular hexagon with side length 12 and radius 10. Find its area.

Mathematics

2 answers:

Paha777 [63]2 years ago

6 0

Answer:

its C

Step-by-step explanation:

Strike441 [17]2 years ago

3 0

Answer:

if i was to guess it would be 96 or 120 this one got me stumped also

Step-by-step explanation:

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Help mee plzz :))tyy

Dimas [21]

Step-by-step explanation:

Given prism has:

Length = 5 in, width = 4 in & height = 6 in

Surface area of prism

$2(lw + wh + lh) \\ = 2(5 \times 4 + 4 \times 6 + 5 \times 6) \\ = 2(20 + 24 + 30) \\ = 2 \times 74 \\ = 148 \: {in}^{2} \\$

4 0

3 years ago

Solve the problem x/27=4/9 x=

Monica [59]

Answer: x=12

Step-by-step explanation:

Multiply both sides by 27.
Use this rule: a/b*c=ac/b
Simplify 4×27 to 108.
Simplify 108/9 to 12

$x=\frac{4}{9} *27\\\\x=\frac{4*27}{9} \\\\x=\frac{108}{9} \\\\x=12$

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

7 0

3 years ago

Happy finds and keeps change she finds around her house recently she learned she has all nickels and quarters she has twice as m

alex41 [277]

Answer:

happy has 25 quarters in total

8 0

2 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

Drag each statement to the correct location on the diagram. The diagram shows a planet orbiting the Sun. Fill in each box with t

Nutka1998 [239]

Answer:

top: Direction of gravitational pull

middle: result orbital path

bottom: Velocity and momentum

Step-by-step explanation:

8 0

3 years ago