Answer:
<u><em>All real numbers</em></u>
Step-by-step explanation:
<u><em>We can start out by knowing that</em></u><u><em> the domain of a graph is, the side, to side from the x axis directions. </em></u>
<u><em>We can see that the </em></u><u><em>line continues of the graph shown, meaning it is infinite. </em></u><u><em>Meaning the answer is </em></u><u><em>the domain is all real numbers.</em></u>
<u><em>We can double check by seeing that the other options don't work or aren't enough:</em></u>
<u><em /></u>
<u><em>The first wouldn't work becuase, yes that is part of the answer, but not the whole answer. The same goes for the others as well, they are on the line and are correct, but the best, and full answer is </em></u><u><em>"All real numbers"</em></u>
Since A‘(-1,1) is on the line y=-x, reflecting it about the line doesn't change its coordinate, so A's coordinate is (-1,1). Reflecting B'(-2,1) about y=-x switches both the sign and the number of x and y, so B=(-1,2), and C'(-1,0) becomes C(0,1). Drawing out the graph with the points and the line helps.
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
8 is missing for the table
Answer:
Length of route that passes the mall= 11 miles
Length of route that passes the theater= 13 miles
Step-by-step explanation:
route to school that passes the mall (highlighted in red)
= (x +1) +(x +2)
= 2x +3
route to school that passes the theater (in yellow)
= (2x +1) +x
= 3x +1
Since the first is 2 miles shorter,
2x +3= 3x +1 -2
Simplify:
2x +3= 3x -1
Bring constants to 1 side, x terms to the other:
3x -2x= 3 +1
x= 4
Substitute x=4 to find the length of each route:
Length of the route that passes the mall
= 2x +3
= 2(4) +3
= 8 +3
= 11 miles
Length of route that passes the theater
= 3x +1
= 3(4) +1
= 12 +1
= 13 miles
Alternatively, length of route that passes the theater
= 11 +2= 13 miles since it is 2 miles longer than that which passes the mall.
