Answer:
Yes; SSS;Triangle AYM Triangle EDC The answer will be D is the correct answer choice.
Step-by-step explanation:
Answer:
y = 2x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (0, 2) ← coordinates of intercepts
m =
= 2
Note the line crosses the y- axis at (0, 2) ⇒ c = 2
y = 2x + 2 ← equation of line
The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
![so \: for \: {x}^{2} + 2x - y + 3 = 0](https://tex.z-dn.net/?f=so%20%5C%3A%20for%20%5C%3A%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20-%20y%20%2B%203%20%3D%200)
let's first put it in "y =" standard format:
![y = {x}^{2} + 2x + 3](https://tex.z-dn.net/?f=y%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%2B%203)
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
![y = {(x +1)}^{2} ...\: is \: y = {x}^{2} + 2x + 1](https://tex.z-dn.net/?f=y%20%3D%20%20%7B%28x%20%2B1%29%7D%5E%7B2%7D%20...%5C%3A%20is%20%5C%3A%20y%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%2B%201)
So there's +2 leftover, since 3-1=2; so:
![y = {(x + 1)}^{2} + 2](https://tex.z-dn.net/?f=y%20%3D%20%20%7B%28x%20%2B%201%29%7D%5E%7B2%7D%20%20%2B%202)
Now we'll subtract the 2 from both sides to show our vertex:
![y - 2 = {(x + 1)}^{2}](https://tex.z-dn.net/?f=y%20-%202%20%3D%20%20%7B%28x%20%2B%201%29%7D%5E%7B2%7D%20)
where our vertex (h, k) is at (-1, 2)