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PilotLPTM [1.2K]
2 years ago
6

Please help me, 65 points to someone who can help me.

Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
7 0
X= -1/2, -11/2 or in decimal form x=-0.5, -5.5
givi [52]2 years ago
3 0

Answer:

  • <u>x = -0.5 , x = -5.5</u>

Step-by-step explanation:

<u>Solving</u>

  • -4x² = 24x + 11
  • 4x² + 24x + 11 = 0
  • 4x² + 24x + 36 - 36 + 11 = 0
  • (2x + 6)² - 25 = 0
  • (2x + 6)² = 25
  • ⇒ 2x + 6 = ±5

<u>Case 1 : x = +5</u>

  • 2x + 6 = 5
  • 2x = -1
  • x = -1/2
  • <u>x = -0.5</u>

<u></u>

<u>Case 2 : x = -5</u>

  • 2x + 6 =  -5
  • 2x = -11
  • x = -11/2
  • <u>x = -5.5</u>
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Solve the following literal equation for y. -7x+8y=11
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3 0
1 year ago
He list shows the growth in centimeters of 12 plants during one week. 6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14 Which box plot best
kumpel [21]

Answer:

Step-by-step explanation:

Hello!

You have the growth of 12 plants over a week (cm)

To construct a box plot you have to identify the 1st, 2nd, and 3rd Quartiles for the box and the maximum and minimum values for the whiskers.

Box

1st Quartile (Q₁)

Is the value of the data set that separates the bottom 25% from the top 75%. First, you need to calculate its position:

PosQ₁= n/4= 12/4= 3

So the first quartile is the third value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₁= 7

2nd Quartile/ Median (Q₂/Me)

PosMe= 12/2= 6

The second quartile in the 6th value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₂=Me= 8

3rd Quartile (Q₃)

PosQ₃= n*(3/4)= 12*(3/4)= 9

The third quartile is the 9th value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₃= 10

The left whisker extends from the Q₁ to the minimum value.

The right whisker extends from the Q₃ to the maximum value.

Min= 6

Max= 14

'------|     |      |-------'

6     7    8    10    14

The box plot that best displays a summary of the data, is C.

I hope this helps!

3 0
3 years ago
A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is
miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0
3 years ago
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