Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Answer:
Addition Property of Equality
Step-by-step explanation:
So we had:
And then we got:
We did this by adding 2 to both sides of the equation. When we added 2, the left side cancelled and the right side equated to 9:
Since we added 2 to both sides, this is an example of the addition property of equality.