6 * 2.5
2 * 2.5
15 cookies
5 brownies
hope i helped
Answer:
Step-by-step explanation:
Given y = coskt
y' = -ksinkt
y'' = -k²coskt
Substitute this y'' into the expression 25y'' = −16y
25(-k²coskt) = -16(coskt)
25k²coskt = 16(coskt)
25k² = 16
k² = 16/25
k = ±√16/25
k = ±4/5
b) from the DE 25y'' = −16y
Rearrange
25y''+16y = 0
Expressing using auxiliary equation
25m² + 16 = 0
25m² = -16
m² = -16/25
m = ±4/5 I
m = 0+4/5 I
Since the auxiliary root is complex number
The solution to the DE will be expressed as;
y = Asinmt + Bsinmt
Since k = m
y = Asinkt+Bsinkt where A and B are constants
Answer:
9,7,5,3,1 is the correct fx in the table
Answer:
Mean = 15.15
Standard deviation = 0.6062
Step-by-step explanation:
We are given a uniform distribution of quantity to be put in each bag.
Low and high filling weights:
14.1 pounds and 16.2 pounds
a = 14.1
b = 16.2
a) Mean:
b) Standard Deviation:
Answer:
It should be 21.1
Step-by-step explanation:
