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Alborosie
3 years ago
6

The two points on the graph are given by the linear function f. a. Use the two points to find the equation that represents the l

inear function f. b. What is​ f(6)? -1 1 2 3 4 5 -1 1 2 3 x y x y graph a. The equation nothing represents the linear function f. ​(Simplify your answer. Type an equation using x and y as the variables. Use integers or fractions for any numbers in the​ equation.)
Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

I dontnflippin know somee

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How to solve -13=5(1 4m)-2m?
Paladinen [302]
First, you would multiply: -13 = 70m - 2m. Then, you subtract the like terms, which would be 70m - 2m: -13 = 68m. You are looking for what m is, so you would divide 68 on both sides: m = - 13 / 68. In math, people would usually like fractions more than decimals, but if you are looking for the decimal number, it would be m ≈ - 0.19.
6 0
3 years ago
A line with a slope of 1/3 passes through the point (-8,9). What is its equation in point-slope form?
BARSIC [14]

Answer:

y - 9 = 1/3 (x+8)

Step-by-step explanation:

point slope form is y - y1 = m (x - x1)

8 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
Nataliya [291]

Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

8 0
3 years ago
F(x) = Vx - 14. Find the inverse of f(x).
olganol [36]

b

Step-by-step explanation:

<h3>correct me if im wrong </h3>
6 0
2 years ago
Read 2 more answers
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