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3 years ago

12

there are eight students in a class two boys and six girls if the teacher picks a group of 5 at random what is the probability t

hat everyone in the group it’s a girl?

1 answer:

VLD [36.1K]3 years ago

6 0

Answer:

like a 80 to 90% probability

Step-by-step explanation:

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I don't get this one plz help

ololo11 [35]

Isocoleese means 2 angles are same, normally the base angles

so since it says they measure 42
rememeber that all angles in traingle add to 180
so base angles+vertex angle=180
base angles aer both 42 so
2 times 42+vertex angle=180
42 times 2=84
so
if veretx angle=z then
84+z=180

answer is B

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2 years ago

Write the contrapositive of the conditional statement. Determine whether the contrapositive is true or false. If it is false, fi

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If you are 16 years old then you are a teenager Question 14

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3 years ago

The circle below is centered at the point (4,3) and has a radius length 5. What is its equation

Crazy boy [7]

The equation of a circle centred at point (m,n) and radius r is given by

<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5

Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
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The equation of the circle is x² + y² - 8x - 6y = 0

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2 years ago

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The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

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2 years ago