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nignag [31]
2 years ago
9

If you get it right you get a brainliest a follow and a like on your profile

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
6 0

Answer:

I Think Answer is

2/5

I think

34kurt2 years ago
4 0

Answer:

The answer is 2/5

Step-by-step explanation:

I hope this was right please mark me brainliest.

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PEMDAS, Awnser is 6 and for the 20 characters Awnser thing I’m typing this
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3 years ago
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Which number is larger: -10 -8 -21 -15?
Cloud [144]

Answer:

I think is -8

Step-by-step explanation:

if you do a line, -8 it's close to cero, which is almost a positive number.

7 0
3 years ago
The graph shows the relationship between the hours a soccer team practiced after the season started and their total practice tim
Sergio [31]

Answer:

6 hours

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Let

x ----> the hours a soccer team practiced after the season started

y ----> the  total practice time for the year in hours

we know that

The y-intercept of a linear equation is the value of x when the value of y is equal to zero

In the context of this problem, the y-intercept is the  total practice time before the season began (the value of x is equal to zero)

Looking at the graph

The y-intercept is the point (0,6)

therefore

the  total practice time before the season began is 6 hours

5 0
2 years ago
evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha
dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

a

The Fermi function for the energy KT is  F(E_o) =  0.2689

b

The temperature is  T_k  =  1261 \  K

Step-by-step explanation:

From the question we are told that

   The energy considered is  E = 0.5 eV

Generally the Fermi  function is mathematically represented as

       F(E_o) =  \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }

    Here K is the Boltzmann constant with value k = 1.380649 *10^{-23} J/K

            E_F  is the Fermi energy

            E_o  is the initial energy level which is mathematically represented as

     E_o = E_F + KT

So

     F(E_o) =  \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{\frac{KT}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{ 1 } + 1}

=>   F(E_o) =  0.2689

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the  Fermi  function as

     F(E_k) =  \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 }  = 0.01

HereE_k is that energy level that is  0.5 ev above the Fermi energy  E_k = 0.5 eV  + E_F

=>   F(E_k) =  \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 }  = 0.01

=>   \frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 }  = 0.01

=>   1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01

=>   0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }

=>   e^{\frac{0.50 eV ]}{KT_k} }  = 99

Taking natural  log of both sides

=>   \frac{0.50 eV }{KT_k} }  =4.5951

=>    0.50 eV   =4.5951 *  K *  T_k

Note eV is electron volt and the equivalence in Joule is     eV  =  1.60 *10^{-19} \  J

So

     0.50 * 1.60 *10^{-19 }   =4.5951 *  1.380649 *10^{-23} *  T_k

=>   T_k  =  1261 \  K

7 0
2 years ago
Find the 10th term of the geometric sequence 1, 3, 9, ...
ladessa [460]

Answer:

a(10) = 3^9 = 19683

Step-by-step explanation:

In this sequence each new term is equal to 3 times the previous term.  Thus, 3 is the common ratio.  The first term is 1.

The general formula for the nth term of a geometric sequence i

a(n) = a(1)*r^(n -1), where r is the common ratio.

Here, a(n) = 1*3^(n - 1), and so

the 10th term is

           a(10) = 1*3^(10 - 1), or

            a(10) = 3^9 = 19683

3 0
2 years ago
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