2 years ago

1.

Mathematics

1 answer:

Mariana [72]2 years ago

3 0

Answer:

1529

Step-by-step explanation:

203*12=2436

now it subtraction 2436-907=1529

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PLEASE HELP<br><br> h(3) = 5x2^-x , Evaluate the function h (3)

Ksju [112]

H (x) = 5 x 2^-x

2^-x is the same as saying 1/2^x .

h (x) = 5 x 1/2^x

h (3) = 5 x 1/2^3
= 5 x 1/8
= 5/8

Therefore h (3) = 5/8

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Write a sine function that has a midline of 5, an amplitude of 4 and a period of 3pi/2

soldi70 [24.7K]

Answer:

Step-by-step explanation:

The standard form for this function is

y = Asin(Bx - C) + D where

A is the amplitude,

B is used to find the period in the formula $period=\frac{2\pi}{B}$ ,

C is used to find the phase shift in the formula $ps=\frac{C}{B}$ ,

and D is the midline which either moves the function up or down from its natural midline of 0.

We have no given phase shift, so there is no C value. The amplitude is easy; we just fill in A as 4. The period is another story:

$\frac{3\pi}{2} =\frac{2\pi}{B}$ and we solve for B by cross multiplying:

3πB = 4π and

$B=\frac{4\pi}{3\pi}$ so

$B = \frac{4}{3}$ so the function is

$y=4sin(\frac{4}{3}x)+5$

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3 years ago

Eight hundred and five thousandths in decimal form?

iragen [17]

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