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3 years ago

-10(-3m-10)-3(-8m+3)

Mathematics

1 answer:

photoshop1234 [79]3 years ago

7 0

-10(-3m-10)-3(-8m+3). -10*-3m-10*-10-3*-8m-3*3. 30m+100+24m-9. 30m+24m+100-9. = 54m+91

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mihalych1998 [28]

Answer:

Part 1) Greta's right, the triangle is incorrect.

Part 2) $34,203\ ft$

Part 3) The height of the tree is $23.3\ ft$ , Trey’s house is not at risk

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(30\°)=\frac{1}{2}$

$sin(30\°)=\frac{6\sqrt{3}}{12}=\frac{\sqrt{3}}{2}$

Compare

$\frac{1}{2}\neq\frac{\sqrt{3}}{2}$

therefore

The triangle is not correct

Because

The side adjacent to the 30 degree angle should be $6\sqrt{3}$ and the side opposite the 30 degree angle should be $6$

Part 2)

Let

x--------> the distance from the airplane to the SCCA (hypotenuse of the right triangle)

we know that

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$x=\frac{10,000}{sin(17\°)}$

$x=34,203\ ft$

Part 3)

Let

x--------> the height of the tree

we know that

$tan(43\°)=\frac{h}{25}$

$h=tan(43\°)(25)=23.3\ ft$

$23.3\ ft< 25\ ft$

therefore

Trey’s house is not at risk

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Answer:

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Answer:

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evablogger [386]

Answer:

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Step-by-step explanation:

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