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lisov135 [29]
4 years ago
15

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,

1). The finishing point will be at (1, −5.3).
A four-quadrant coordinate grid is drawn from negative 4 to positive 4. Quadrant I is labeled Quadrant P, Quadrant II is labeled Quadrant Q, Quadrant III is labeled Quadrant R, and Quadrant IV is labeled Quadrant S.


Part A: Use the grid to determine in which quadrants the starting point and the finishing point are located. Explain how you determined the locations. (6 points)


Part B: A checkpoint will be at (5.3, 1). In at least two sentences, describe the difference between the coordinates of the starting point and the checkpoint, and explain how the points are related. (4 points)

Mathematics
1 answer:
timurjin [86]4 years ago
5 0

Answer:

starting point Quadrant Q

Finishing point Quadrant  S

B- the check point will be in Quadrant p, since the two values of x and y are positive. the two points are  on a horizontal line 10.6 apart.

Step-by-step explanation:

A- because x value is negative and y- is positive it is Q

    x value is positive and y negative it is S

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Answer:

127.31

Step-by-step explanation:

127.31

7 0
3 years ago
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11 Yesterday 170 guests at a hotel called for room service, and 255 guests did not call for room
-Dominant- [34]

Answer:

The percentage of the guests at this hotel called for room service yesterday is 40%

Step-by-step explanation:

We are given

total number of guests called for room services =170

total number of guests did not called for room services =255

now, we can find total number of guests

Total number of guests =(total number of guests called for room services)+(total number of guests did not called for room services)

so,

total number of guests is

=170+255

=425

now, we can find percentage

percentage of the guests at this hotel called for room service yesterday is

%

So,

The percentage of the guests at this hotel called for room service yesterday is 40%

5 0
3 years ago
Geometry Help!!!
dem82 [27]
<h3>Answer: Choice A) 24.0</h3>

===============================

Explanation:

Let's say we had a triangle with side lengths a,b,c.

If we know that a = 12.25 and b = 12.25, then the third side c has its length restricted in such a way that

b-a < c < b+a

This is a variation of the triangle inequality theorem.

-------------

So,

b - a < c < b + a

12.25 - 12.25 < c < 12.25 + 12.25

0 < c < 24.5

which means the third side c is between 0 inches and 24.5 inches.

The value of c cannot be 0, and it cannot be 24.5 either.

Among the answer choices given, we see that only 24.0 is the only valid option here. The other two choices are too large.

-------------

Side Note: If your teacher gave you two angles (instead of two sides) to be 12.25 degrees, and wanted the third missing angle of the triangle, then you would be correct in having 12.25+12.25+x = 180 as your first step.

4 0
3 years ago
When solving an equation like x3 = 64, why does our solution not include the negative cube root?
MAVERICK [17]
So I’m only answering so I can ask you a question
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2 years ago
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what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
3 years ago
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