9m+14=2m How do I solve and check answer?

A worker at a factory earns $12 per hour plus 2.50 for each unit produced that hour. The worker earns a total of $27 in one hour

nevsk [136]

Answer:

The total number of units produced is 6 .

Step-by-step explanation:

Given as :

The earning of worker at the factory = $ 12 per hour + $ 2.50 each unit per hour

The total earning of worker per hour = $ 27

Let The total number of unit produced = x

According to question

The wage worker earn per hour + earning × per unit produced that hour = Total earning of worker per hour

Or, $ 12 per hour + $ 2.50 each unit per hour × x = $ 27

Or, $ 2.50 each unit per hour × x = $ 27 - $ 12

Or, $ 2.50 each unit per hour × x = $ 15

∴ x = $\frac{15}{2.50}$

Or, x = 6

Hence The total number of units produced is 6 . Answer

4 0

3 years ago

I

posledela

Answer:

6(x-8)=5-2x

Step-by-step explanation:

let the number be x

so we have six times the difference between a number and 8

that is 6(x-8).

is equal to 5 less than twice the number ..we have

=5-2x.

therefore, our answer becomes:

6(x-8)=5-2x

5 0

3 years ago

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant = 0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

$N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g$

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0

3 years ago

Help I’m stuck on this question I’ve been stuck on it for a while I can’t seem to figure it out please help for ten points

Naddika [18.5K]

Answer:

$\frac{1}{25}$

Step-by-step explanation:

I think what it is trying to say is that it wants the solution to multiplying all of those. The (...) simply means that it wants you to continue that pattern in what you are supposed to be multiplying, but stop at $\frac{24}{25}$ .

That would mean you are technically supposed to be multiplying:

$\frac{1}{2} \frac{2}{3} \frac{3}{4} \frac{4}{5} \frac{5}{6} \frac{6}{7} \frac{7}{8} \frac{8}{9} \frac{9}{10} \frac{10}{11} \frac{11}{12} \frac{12}{13} \frac{13}{14} \frac{14}{15} \frac{15}{16} \frac{16}{17} \frac{17}{18} \frac{18}{19} \frac{19}{20} \frac{20}{21} \frac{21}{22} \frac{22}{23} \frac{23}{24} \frac{24}{25}$

That is a lot and unfortunately, none of the individual fractions can be simplified within that. The final answer would be able to be simplified, though.

Multiplying the first four shown: $\frac{1}{2}\frac{2}{3} \frac{3}{4} \frac{4}{5}$ you end up with $\frac{24}{120}$ . Both the numerator (top) and the denominator (bottom) are divisible by 24. Dividing top and bottom would simplify this to $\frac{1}{5}$ .

Now, let's take the next four.

$\frac{5}{6}\frac{6}{7} \frac{7}{8} \frac{8}{9}$ allows you to end up with $\frac{1680}{3024}$ . Both the numerator (top) and the denominator (bottom) are divisible by 336. You are left with $\frac{5}{9}$ .

Now, let's take the next four.

$\frac{9}{10}\frac{10}{11} \frac{11}{12} \frac{12}{13}$ . Multiplying these gives you $\frac{11880}{17160}$ . Both the numerator (top) and the denominator (bottom) are divisible by 1320. You are left with $\frac{9}{13}$ .

Now, let's take the next four.

$\frac{13}{14}\frac{14}{15} \frac{15}{16} \frac{16}{17}$ . Multiplying these gives you $\frac{43680}{57120}$ . Both the numerator (top) and the denominator (bottom) are divisible by 3360. You are left with $\frac{13}{17}$ .

* Although I would continue to say let's take the next four, there appears to be a pattern in the simplification. The numerators we have gotten have all been four less than their denominators, and each numerator has been four more than the last. I cannot be certain, but we only have two sets of four left. If this pattern continues, the simplifications of each should be $\frac{17}{21}$ and $\frac{21}{25}$ . I will continue on for argument's sake, anyways.

The next four are $\frac{17}{18}\frac{18}{19} \frac{19}{20} \frac{20}{21}$ . Multiplying these, you are left with $\frac{116280}{143640}$ . Both the numerator (top) and the denominator (bottom) are divisible by 6840. We are left with $\frac{17}{21}$ . This is the exact guess I had made when following the pattern, and so the next one is most likely going to be the other guess as well.

Our final answer will be $\frac{1}{5}\frac{5}{9} \frac{9}{13} \frac{13}{17}\frac{17}{21} \frac{21}{25}$ all multiplied together. We end up with $\frac{208845}{5221125}$ . Both the numerator (top) and denominator (bottom) are divisible by 208845.

Simplified, your final answer is: $\frac{1}{25}$ .

* NOTE: that another way to solve this would just be to multiply all numbers from 1-24 together and then 2-25, but you would end up with a very large number that would be just as time consuming to simplify. To get the GCF fast, I used a GCF calculator.

6 0

3 years ago

Can someone help answer this

kolezko [41]

Answer:

v = 55

Step-by-step explanation:

Plug in the values provided into the equation

v = u + at

v = 23 + 8 * 4

Solve

v = 23 + 8 * 4

v = 23 + 32

v = 55

6 0

3 years ago

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