Answer:
The length of the sides are 9 units, 18 units and 11 units
Step-by-step explanation:
Let
x ----> one side of the triangle
y ----> the longest side of the triangle
z ----> the third side of the triangle
we know that
The perimeter of triangle is equal to

we have

so
----> equation A
-----> equation B
----> equation C
substitute equation B and equation C in equation A
solve for y


<em>Find the value of x</em>
---> 
<em>Find the value of z</em>
----> 
therefore
The length of the sides are 9 units, 18 units and 11 units
We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
For this case we have the following expression:
Using the associative property we can rewrite the expression in the following way:
Finally, simplifying we have:
Answer:
Rewriting the expression we have that the result is:
d. -7