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4 years ago

How many permutations exist of the letters a, b, c, d taken four at a time?

1 answer:

3 0

There are 24 permutations.

The number of permutations of 4 objects taken 4 at a time is given by
4!/(4-4)! = 4!/0! = 4!/1 = 4! = 24

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Simplify the following expression: (5x2 + 3x + 4) − (2x2 − 6x + 3). If the final answer is written in the form Ax2 + Bx + C, wha

deff fn [24]

Question 1 Simplify the following expression: (5x2 + 3x + 4) − (2x2 − 6x + 3). If the final answer is written in the form Ax2 + Bx + C, what is the value of B?
Solution:
5x^2 + 3x + 4 - 2x^2 + 6x - 3 = 3x^2 + 9x + 1
Then, B = 9 Hope this helped=)

5 0

4 years ago

When you subtract two positive integers is result always a positive integer

Olin [163]

Not always, for example 19-32 that would answer to a negative if it was like this : 9-1 then it would be okay message me if u need more help or u dont understand

6 0

3 years ago

Hello Guys I Need Help With This 5th-grade math question Please help me out I will Mark As Brainlist if the answer is correct! (

luda_lava [24]

Answer:

1/9 = 1/45*5

Step-by-step explanation:

When you divide by something, you multiply by its reciprocal so...

1/9 * 1/5=1/45

Now we need to know what 1/9 equals so we can divide both sides by 1/5

1/9=1/45 divided by 1/5

Again you need to multiply by its reciprocal

1/9 = 1/45*5

3 0

3 years ago

Read 2 more answers

If c varies directly as the square root of d, and c=14, when d = 64, find c when d= 324

zubka84 [21]

Answer:

c = 31.5

Step-by-step explanation:

Given c varies directly as $\sqrt{d}$ then the equation relating them is

c = k $\sqrt{d}$ ← k is the constant of variation

To find k use the condition c = 14 when d = 64, then

14 = k × $\sqrt{64}$ = 8k ( divide both sides by 8 )

1.75 = k

c = 1.75 $\sqrt{d}$ ← equation of variation

When d = 324 , then

c = 1.75 × $\sqrt{324}$ = 1.75 × 18 = 31.5

5 0

3 years ago

The Scott family is trying to save as much money as possible. One way to cut back on the money they spend is by finding deals wh

avanturin [10]

Answer:

Unit price of strawberries at Grocery Mart is $ 1.495 or 150 pennies

Unit price of strawberries at Baldwin Hills Market is $ 1.33 or 133 pennies.

Step-by-step explanation:

1 dollar = 100 pennies

Given:

Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

∵ Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

∴ Cost of 1 pound of strawberries at Grocery Mart = $\frac{2.99}{2}=\$1.495=1.495\times 100\approx 150\textrm{ pennies}$

∵ Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

Cost of 1 pound of strawberries at Baldwin Hills Market = $\frac{3.99}{3}=\$1.33= 1.33\times 100 = 133\textrm{ pennies}$

Therefore, the unit price of strawberries at each grocery store is the cost of 1 pound of strawberries. So, unit rate at Grocery Mart is 150 pennies and at Baldwin Hills Market is 133 pennies.

7 0

3 years ago