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3 years ago

How many permutations exist of the letters a, b, c, d taken four at a time?

1 answer:

3 0

There are 24 permutations.

The number of permutations of 4 objects taken 4 at a time is given by
4!/(4-4)! = 4!/0! = 4!/1 = 4! = 24

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which uppercase letters will not appear reversed when they are held in front of a mirror? what type of symmetry do these letters

Irina-Kira [14]

A,H,I,M,O,T,U,V,W,X,Y --- these have vertical symmetry

a word whose reflection is also a word....YAM and MAY

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3 years ago

A major car dealership has several stores in a big city. The owner wants to determine if there is a difference in the proportion

Gemiola [76]

Answer:

confidence interval = ( -0.38 , 0.08 )

Step-by-step explanation:

Given data :

n1 = 55 , n2 = 60 ,

Let P1 ( proportion of SUV sales at store A ) = 30 / 55 = 0.55

P2 ( sample proportion of SUV sales at store B ) = 42/60 = 0.70

The Z-value at 99% confidence Interval = 2.58

<u>Determine the 99% confidence interval for difference in proportion</u>

applying the formula below

( P1 - P2 ) ± Z ( $\sqrt{p1( 1-p1)/n1 + p2(1-p2)/n2}$

Input values above into equation

confidence interval = ( -0.38 , 0.08 )

5 0

3 years ago

What is the probability of rolling a 10 out a 12 sided die

lions [1.4K]

1/12

There is 1 side of the die that has a ten on it and 12 sides in total. Therefore, there is a 1/12 chance of rolling a ten on this die.

5 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

A line passes through the point (3,1) and has a slope of 2.<br><br> what is the y-intercept?

Valentin [98]

The y intercept would be -5

7 0

2 years ago

Read 2 more answers