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3 years ago

Can y’all help me on question 3?!

Mathematics

2 answers:

nexus9112 [7]3 years ago

6 0

Answer:

Isha needs 60 gallons of paints to the wall.

Step-by-step explanation:

The area of trapezoid shaped like wall is given by :-

Area of trapezoid = 1/2 × ( Base ¹ + Base ² ) × H

Where,

B ¹ and B ² are the length of bases and H is the perpendicular distance between them.

Area of wall = 1/2 × ( Base¹ + Base²) × Height

Where, according to question we have

Base ¹ = 5 t
Base ² = 15 ft
And , Height = 6 ft

substitute the values

Area = 1/2 × ( 5 ft + 15 ft ) × 6 ft

add the values of Base¹ and Base ²

Area = 1/2 × 20 ft × 6 ft

multiply

Area = 1 / 2 × 120 ft ²

divide

Area = 120 ft ² / 2 = 60 ft ²

It takes 1 gallon to cover 1 ft ². ... ( given)

So, For covering 60 ft ² it takes 60 gallons .

check

( 1 × 60 ) gallon = 60 ft ²

60 gallon = 60 ft²

Charra [1.4K]3 years ago

4 0

9514 1404 393

Answer:

60 gallons

Step-by-step explanation:

The area of the trapezoid-shaped wall is given by ...

A = 1/2(b1 +b2)h

where b1 and b2 are the lengths of the parallel sides, and h is the perpendicular distance between them.

The area of the wall is ...

A = (1/2)(5 ft + 15 ft)(6 ft) = 60 ft²

If it takes 1 gallon to cover 1 square foot, then it will take 60 gallons to cover 60 square feet.

Isha needs 60 gallons of paint.

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Given the triangle below, answer the following:

OLEGan [10]

Answer:

Step-by-step explanation:

question no . 5

ratio of angle L

take angle as reference angle

using cos rule

cos L = base / hypotenuse

= 4/5

ratio of angle N

take angle N as reference angle

using sin rule

sin N = opposite / hypotenuse

= 4/5

for measure of angle L

cos L = 4/5

cos L = 0.8

L = $cos^{-1}(0.8)$

L = 36.9

for meanure of angle N

sin N = 4/5

sin N = 0.8

N = $sin^{-1}(0.8)$

N = 53.1

7 0

3 years ago

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Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i

Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

$a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333$

So the correct answer is C, the area between the two functions is 4/3 units.

3 0

3 years ago

What is 2.3*2.1 Please find the answer

anygoal [31]

Answer: 4.83

Step-by-step explanation:

2.3*2.1= 4.83

7 0

4 years ago

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The diagram shows parallel lines cut by two transversal lines creating a triangle. Which statements are true? Check all that app

vitfil [10]

Answer:

$m$

Step-by-step explanation:

<u>Verify each statement</u>

case A) $m$

The statement is True

we know that

The measure of angle A is equal to the angle marked $20\°$ by corresponding angles

case B) ∠B and the angle marked $60\°$ are alternate exterior angles

The statement is False

Because, ∠B and the angle marked $60\°$ are corresponding angles

case C) $m$ because it is a vertical angle to the angle marked $100\°$

The statement is True

we know that

$m$ ------> by vertical angles

case D) ∠B and ∠C are supplementary angles

The statement is False

we know that

$m$ ---> the sum is less than $180\°$

case E) $m$

The statement is True

we know that

$m$

and remember that

$m$

substitute

$m$

3 0

3 years ago

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The two-way table shows the number of people who have or have not graduated from college and who live or do not live in their ho

neonofarm [45]

Answer:

0.28

Step-by-step explanation:

Refer the attached figure

Given :

People who live in their hometown and graduated from the college =8

People who do not live in their hometown and graduated from the college = 10

People who did not graduate from college and lives in home town = 6

People who did not graduate from college and do not live in home town = 4

To Find : Among people who do not live in their hometown, what is the relative frequency of not graduating from college?

Solution :

The total no. of people who do not live in home town whether they are graduated or not graduated = 14

People who did not graduate from college and do not live in home town = 4

Thus Among people who do not live in their hometown the relative frequency of not graduating from college :

People who did not graduate from college and do not live in home town/total no. of people who do not live in home town whether they are graduated or not graduated

⇒ $\frac{4}{14}$

⇒ $\frac{2}{7}$

⇒ $0.28$

Thus , Among people who do not live in their hometown the relative frequency of not graduating from college = 0.28

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4 years ago

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