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lilavasa [31]
3 years ago
9

These two triangles can be shown to be congruent using which transformation?

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0

Answer:

This is B) A reflection over the y-axis.

Step-by-step explanation:

You can tell this in a picture due to the fact that each point on the corresponding triangle is equidistant from the y-axis. Take the point at the bottom for instance. In both pictures, it is 2 spaces away from the y axis.

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Find the constant of proportional (r) in the equation y = rx​
RUDIKE [14]

Answer:

Constant of proportionality,  

Step-by-step explanation:

Constant of proportionality states that the constant value of the ratio of two proportional quantities x and y,

it is written in the form of y = kx, where k is the constant of proportionality.

Given the equation:                         .....[1]

where r is the constant of proportionality.

From the table we consider

x = 14 and y = 1.4

Substitute these given values in [1] to solve for r;

Divide both sides by 14 we get;

therefore, the Constant of proportionality,  

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3 years ago
PLEASE HELP ASAP! 20 POINTS AND ILL GIVE YOU A BRAINLIEST!!
nikitadnepr [17]
It is A because you are adding 3 to in if you were to subtract then it will go down not up.
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Three guys rent a hotel room for the night. When they get to the hotel they pay the $30 fee, then go up to their room. Soon the
loris [4]

Answer:

I didnt understand but lets just say the bellhop took ot

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2 years ago
What is 31 billion in scientific notation?
zepelin [54]

Answer:

(3.10 x 10^10)

Step-by-step explanation:

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3 years ago
Read 2 more answers
Assume we cut the last piece of the pie into two sections (1 and 2) along ray BD
earnstyle [38]

Answer:

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

Step-by-step explanation:

From statement, we know that measure of the angle ABC is equal to the sum of measures of angles ABD (<em>section 1</em>) and DBC (<em>section 2</em>), that is to say:

m \angle ABC = m\angle ABD + m\angle DBC (1)

If we know that m\angle ABC = 40^{\circ}, m\angle ABD = 2\cdot x + 3 and m\angle DBC = 4\cdot x + 7, then the value of x is:

(2\cdot x + 3)+(4\cdot x + 7) = 40^{\circ}

6\cdot x +10^{\circ} = 40^{\circ}

6\cdot x = 30^{\circ}

x = 5

Then, we check the angles of each section:

Section 1

m\angle ABD = 2\cdot x + 3

m\angle ABD = 13^{\circ}

Section 2

m\angle DBC = 4\cdot x + 7

m\angle DBC = 27^{\circ}

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

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