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Angelina_Jolie [31]
3 years ago
7

Stefanie is painting her bedroom. She can paint square feet in of an hour. How many square feet can she paint in one hour?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0
In what of in hour tho???
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The perimeter of and equilateral triangle is 60mm. What is the size of the other side?
Alex

Answer:

20mm

Since it a equilateral triangle we know that there is 3 sides and all of them are euqal. Therefore, 60/3 =20 meaning each side is 20mm.

8 0
3 years ago
What is the value of (y^-5/x^-3) for x = 2 and y = -4
Anastasy [175]
-1/1024)/(1/8
-1/1024)x 8
-8/1024
-1/128
5 0
3 years ago
Plz help! It’s not hard I just don’t properly understand
jonny [76]

Answer:

a_{13}=2(13)+13=39

39 is the 13th term

Step-by-step explanation:

Okay so essentially the a_n is just a substitute for x.

See how in the equation they put n into the x spot:

y=mx+b\\a_n=mn+b\\a_n=2n+13

They changed the variable names:

y=a_n\\m=2\\n=x\\b=13

Now we know what the n actually means, plus when they ask about the terms youre trying to find it's based off of that n:

When they say, 13 term, they mean a_{13} which would be the 13th answer in the series.  So the first term would be based off of a_1

a_1=2(1)+13\\a_1=15

So whatever number is in the n position by a is what you'll be plugging into the x spot.

y=mx+b\\a_n=2n+13\\a_1=2(1)+13=15\\a_2=2(2)+13=17\\a_3=2(3)+13=19\\a_4=2(4)+13=21\\a_5=2(5) +13=23\\a_6=2(6)+13=25\\a_7=2(7)+13=27\\a_8=2(8) +13=29\\a_9=2(9)+13=31\\a_{10}=2(10)+13=33\\a_{11}=2(11)+13=35\\a_{12}=2(12)+13=37\\a_{13}=2(13)+13=39

These are all the answers leading up to the 13th term they asked for, and you can continue thus same equation with whatever number you can put into the n space.

7 0
2 years ago
2z - 31 = -9z + 24
SpyIntel [72]
You would combine like terms so the answer would be -7z-7
6 0
3 years ago
Read 2 more answers
Find how many positive integers with exactly four decimal digits, that is, positive integers between 1000 and 9999 inclusive, ha
zmey [24]

Answer:

(a) There are 257 numbers which are divisible by 5 and by 7

(b) There are 1286 numbers which are divisible by 7

(c) There are 4500 even numbers

(d) There are 514 numbers which are divisible by 5 but not by 7

Step-by-step explanation:

(a) Since, LCM(5, 7) = 35,

Thus, the numbers divisible by 5 and by 7 between 1000 and 9999,

1015, 1050, 1085............, 9975

Which is an AP,

Having first term, a = 1015,

Common difference, d = 35,

Last term, l = 9975

If n be the number of terms,

\because l = a + (n-1)d

9975 = 1015 + (n-1)35

9975 - 1015 = (n-1)35

8960 = (n-1)35

256 = n-1

\implies n = 256 + 1 = 257

(b) Similarly,  number divisible by 7,

1001, 1008, 1015............, 9996

Here, a = 1001, d = 7, l = 9996

9996 = 1001 + (n-1)7

9996 - 1001 = (n-1)7

8995 = (n-1)7

1285 = n-1

\implies n = 1285 + 1 = 1286

(c) Even numbers between 1000 and 9999 inclusive

1000, 1002, 1004, 1006,........9998

Here, a = 1000, d = 2, l = 9998

9998 = 1000 + (n-1)2

9998 - 1000 = (n-1)2

8998 = (n-1)2

4499 = n-1

\implies n = 4499 + 1 = 4500

(d) Number divisible by 5,

1000, 1005, 1010............, 9995

Here, a = 1000, d = 5, l = 9995

9995 = 1000 + (n-1)5

9995 - 1000 = (n-1)5

8995 = (n-1)5

1799 = n-1

\implies n = 1799 + 1 = 1800

Hence, the number divisible by 5 but not by 7 = numbers divisible by 5 - number divisible by 7

= 1800 - 1286

= 514

8 0
4 years ago
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