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FromTheMoon [43]
3 years ago
9

Help need answers to this asap

Mathematics
1 answer:
k0ka [10]3 years ago
3 0
Here it is we used the formula of the lateral area of the cylinder

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What is the equation of the quadratic function whose zeros are -2 and 5? *
zaharov [31]

Step-by-step explanation:

here is your answer Hope you will enjoy and mark me as brainlist

thank you

7 0
3 years ago
Find the volume of the given prism round to nearest tenth
allochka39001 [22]

Answer:

308.2

Step-by-step explanation:

A=2(wl+hl+hw)=2*(3.9*13.2+6*13.2+6*3.9)≈308.16cm^2

≈ is approximately

3 0
3 years ago
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Solve the inequality 4(k − 5) + 12k ≥ −4
IgorC [24]

Answer:

k ≥ 1

Step-by-step explanation:

Step 1: Write inequality

4(k - 5) + 12k ≥ -4

Step 2: Solve for <em>k</em>

  1. Distribute 4: 4k - 20 + 12k ≥ -4
  2. Combine like terms: 16k - 20 ≥ -4
  3. Add 20 to both sides: 16k ≥ 16
  4. Divide 16 on both sides: k ≥ 1
5 0
3 years ago
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What is 7/24 times 8/35?
Serga [27]

Answer:

1/15

Step-by-step explanation:

7/24 * 8/35

1/3*1/5=1/15

4 0
3 years ago
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Suppose a punter kicks a football so that the upward component of its velocity is 80 feet per second. If the ball is 3 feet off
Alexxandr [17]
So hmm check the picture below

\bf \qquad \textit{initial velocity}\\\\ h = -16t^2+v_ot+h_o \qquad \text{in feet}\\&#10;\\&#10;v_o=\textit{initial velocity of the object}\\&#10;h_o=\textit{initial height of the object}\\&#10;h=\textit{height of the object at "t" seconds}\\\\&#10;-----------------------------\\\\&#10;h(t)=3+80t-16t^2\iff h(t)=-16t^2+80t+3

a)

well, clearly is 80 ft/s

b)

when t = 1? well 80(1)

c)

in the picture, x-axis is the time and y-axis is the height
so, it reaches its maximum at the vertex, after "x" seconds

\bf \begin{array}{lcccll}&#10;h(t)=&-16t^2&+80t&+3\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

so it reached the vertex after \bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds

d)

the maximum height of the ball is \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet

8 0
3 years ago
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