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3 years ago

Is it right ????????

Mathematics

1 answer:

Korolek [52]3 years ago

6 0

Answer:

yeah

Step-by-step explanation:

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COS (377= 32

Elanso [62]

The answer is c because the remaining number would be 10

4 0

2 years ago

2. Find the gross monthly income from this job and calculate your monthly take-home pay.

Step2247 [10]

Answer:

you will need to know what's his gross monthly income and multiply by 25%that will give you the amount of taxes withheld and then subtract that from gross monthly income and that will give you Monthly take home pay.

4 0

3 years ago

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

ZanzabumX [31]

Answer:

shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.

Step-by-step explanation:

Given: The quadratic equation

We have to show the correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.

The standard form of quadratic equation is then the solution of quadratic equation using quadratic formula is given as

Consider the given quadratic equation

Comparing with general quadratic equation, we have

a = -3 , b = -2 , c = 6

Substitute in quadratic formula, we get,

Simplify, we have,

Thus, and x_{2}=\frac{2-\sqrt{76} }{-6}

Simplify, we get,

Thus, shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.

3 0

2 years ago

What is 4/9 + 7/18 in simplest form?

Lorico [155]

5/6 would be the answer.

8 0

3 years ago

Read 2 more answers

A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i

yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

$T - Ts = (T_0 - Ts)e^k^t$

We'll solve for k

$35 - 100 = (20 - 100)e^9^k$

$-65 = (-80)e^9^k$

Divide both sides by -5

$13 = (16)e^9^k$

$9k = ln (\frac{13}{16})$

$k = \frac{1}{9} ln (\frac{13}{16})$

$k = -0.02307104053$

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

$T - Ts = (T_0 - Ts)e^k^t$

$T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100= -52.8125$

$T = 100 - 52.8125$

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0

3 years ago