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zimovet [89]
3 years ago
15

Is it right ????????

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

yeah

Step-by-step explanation:

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2y+4x=14 is it infinite no solution one solution ??????
lubasha [3.4K]
Solution I think I’m not 100% though:/
6 0
2 years ago
How to do this and I need help pls
tatuchka [14]

Answer:

9

Step-by-step explanation:

f(x) = (x - 2)^{2}  \\ f(5) = (5 - 2)^{2}  \\ f(5) =  {(3)}^{2} \\ f(5) = 3 \times 3 \\ f(5) = 9

7 0
3 years ago
Make x the subject of the formula w − y x = z
Licemer1 [7]

Answer:

hmm ..

just transfer the X at the right side and others on left side

Step-by-step explanation:

so you get

w-z = yx

so later

(w-z)/y = x

3 0
3 years ago
Let f(x)=4x2+5. The function g(x) is f(x) translated up 4 units. Enter the equation of g(x) in the box.
Zepler [3.9K]
Al you have to do is add 4 to the equation
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6 0
3 years ago
Read 2 more answers
A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
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