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a_sh-v [17]
3 years ago
6

What is the slope of the line that passes through the points (–1, –17) and (–4, –2)?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0
Hello!

To find the slope of a line, we use the formula y2-y1/x2-x1.

Each ordered pair can either represent the 1,s or the 2,s and the slope will be the same. For our example, lets have (-1,-17) represent (x1,y1) and (-4.-2) represent (x2,y2). 

We will plug these values into the equation.

-2+17/-4+1
15/-3
-5

The slope of the line is -5, but let's check our answer by switching the 1's and 2's.

-17+2/-1+4
-15/3
-5

The slope of the line is -5.

I hope this helped you!

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The coordinates of point A are (-11 , 2)

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→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

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∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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