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Stells [14]
3 years ago
8

The total value of a collection of nickels and dimes is $3.05. If the number of nickels is 19 greater than the number of dimes,

how many nickels are in the collection?
Mathematics
1 answer:
il63 [147K]3 years ago
8 0

Answer:

N = 33

Step-by-step explanation:

N = D + 19

.05N + .10 D = 3.05

N = 33

D = 14

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Is lmn congruent to opq if so name the postulate
insens350 [35]

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

                   Statements                      Reasons

1). LM ≅ OP                                   1). Given

2). MN ≅ PQ                                 2). Given

3). ∠P ≅  ∠M                                3). Given

4). ΔLNM ≅ ΔOQP                      4). By the SAS postulate of congruence.

                                                         [Side - Angle - Side]                          

Therefore, Option (A) will be the answer.

5 0
4 years ago
Assume the readings on thermometers are normally distributed with a mean of 0degreesc and a standard deviation of 1.00degreesc.
Tanzania [10]

Let Z be the reading on thermometer. Z follows Standard Normal distribution with mean μ =0 and standard deviation σ=1

The probability that randomly selected thermometer reads greater than 2.07 is

P(z > 2.07) = 1 -P(z < 2.07)

Using z score table to find probability below z=2.07

P(Z < 2.07) = 0.9808

P(z > 2.07) = 1- 0.9808

P(z > 2.07) = 0.0192

The probability that a randomly selected thermometer reads greater than 2.07 is 0.0192

3 0
4 years ago
Assume that 0 a) 25/24 b) -25/24 c) 24/25 d) -24/25
ser-zykov [4K]
A) 25/24 because i don’t know i’m just doing this to get points
8 0
3 years ago
Bobby has already ran 1 mile on his own, and he expects to run 1 mile during each track practice. How many track practices would
german

Answer:

In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>

Step-by-step explanation:

Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.

You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.

Setting up an equation will help us solve. Here is how we could set up the equation:

(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)

1 + x = 33

The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.

1 + x = 33

1 - 1 + x = 33 - 1

x = 32

The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.

8 0
3 years ago
F(n+1)=f(n)-3 f(1)=15
Trava [24]

Answer:

f(n+1) = 13

Step-by-step explanation:

  • We know that f(1) = 15
  • So we can substitute this for f(n)-3
  • With this:
  1. f(n+1) = f(1) -3
  2. f(n+1) = 15-2
  3. f(n+1) = 13
5 0
3 years ago
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