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Stells [14]
3 years ago
8

The total value of a collection of nickels and dimes is $3.05. If the number of nickels is 19 greater than the number of dimes,

how many nickels are in the collection?
Mathematics
1 answer:
il63 [147K]3 years ago
8 0

Answer:

N = 33

Step-by-step explanation:

N = D + 19

.05N + .10 D = 3.05

N = 33

D = 14

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3 years ago
Solve the following simultaneous equations : with the help of steps<br>1. x + 2y = 1, 3x - y = 17​
IRISSAK [1]

Answer:

x = 5, y = -2

Step-by-step explanation:

<u>Given equations:</u>

  • x + 2y = 1
  • 3x - y = 17​

<u>From the first equation we get:</u>

  • x = 1 -2y

<u>Substitute x in the second equation, find y:</u>

  • 3x - y = 17
  • 3*(1-2y) - y = 17
  • 3 - 6y - y = 17
  • -7y = 17 - 3
  • -7y = 14
  • y = -14/7
  • y = -2

<u>Find x:</u>

  • x = 1 - 2y
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  • x = 1 + 4
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6 0
3 years ago
What is th GCF of 21 and 18
ZanzabumX [31]

Answer:

The answer is 3.

Explanation:

Factors of 18:

1, 2, 3, 6, 9, 18.

Factors of 21:

1, 3, 7.

The highest number that both sets contain is 3, so the GCF will be 3.


5 0
3 years ago
Read 2 more answers
N = {X:X<br>is an odd number, 21&lt;x&lt;3<br>XEN]​
SIZIF [17.4K]
So it’s saying that the following set in roster form: (1) N = (x :x is an odd number, 21< × ≤ 35,×€ N)?

It seems to be that the Roster form would do not do anything but the thing is that this listing would give us the output of a set from this problem.

Your answer would be, N = Set of Odd Numbers such that x is greater than 21 and less than or equal to 35 = {23, 25, 27, 29, 31, 33, 35}.
5 0
2 years ago
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