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o-na [289]
2 years ago
15

Give an example of 3 detrivores. On what do they feed?

Biology
2 answers:
saw5 [17]2 years ago
4 0

Answer:

Sea cucumber,Vulture,  and worms

they feed on dead organisms

Explanation:

ELEN [110]2 years ago
3 0

Answer:

Vultures, worms, and crabs

Explanation:

they feed on dead organisms

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The human body is composed of cells, organs, organ systems, and tissues. How are these organized?
Pie

Answer:Cells are organized into tissues; and tissues form organs. Organs are organized into organ systems. Example like your muscular system.

Explanation:

7 0
3 years ago
The human genome has<br> number of base pairs <br> Answer
Alborosie

Answer:

The human genome contains approximately 3 billion of these base pairs, which reside in the 23 pairs of chromosomes within the nucleus of all our cells. Each chromosome contains hundreds to thousands of genes, which carry the instructions for making proteins.

4 0
3 years ago
During a windstorm, a large old tree fell in the forest. As it came down, it trapped a young sapling about 5 meters tall underne
just olya [345]
During a windstorm, a large old tree fell in the forest. As it came down, it trapped a young sapling about 5 meters tall underneath it. The top of the 

Auxin and gibberellin in the sapling's stem will cause a gravitropic response in the sapling, and its stop will grow upward even though it is held down. 
5 0
3 years ago
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Jumble letter can you help me plsss​
sveticcg [70]
<h2>Answer</h2>

  1. Wind
  2. Sunlight
  3. Plants
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  5. Coal
  6. Minerals
  7. Water
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\\

In short it's natural resources.

3 0
2 years ago
Suppose a geneticist isolates two bacteriophage mutants. One mutation causes clear plaques (c), and the other produces minute pl
Nesterboy [21]

Answer:

The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.  

Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.  

The total recombinants from 1000 plaques will come out to be 80,  

Thus, the recombinants of each type will be 40.  

Total parental type will be 920, and therefore, each parental type count will be 460.  

Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.

5 0
2 years ago
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