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3 years ago

Solve equation by factoring 8x^2-8x=0

1 answer:

3 0

Answer: x= 0 or x= 1

Step by step:

Step 1: Factor left side of equation.

= 8x (x – 1) = 0

Step 2: Set factors equal to 0.

= 8x = 0 , x = -1 = 0

= x = 0 , x = –1

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Find the product. (n 7)2 n² 14n 14 2n² 14n 49 n² 14n 49.

Marianna [84]

The product of $\rm (n+7)^2$ is $\rm n^2+14n+49$ .

Given

The product of $\rm (n+7)^2$ .

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of $\rm (n+7)^2$ is given by;

$\rm =(n+7)^2\\\\=(n+7)\times (n+7)\\\\= n(n+7)+7(n+7)\\\\=n^2+7n+7n+49\\\\=n^2+14n+49$

Hence, the product of $\rm (n+7)^2$ is $\rm n^2+14n+49$ .

To know more about Multiplication click the link given below.

brainly.com/question/19943359

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Help answering this simple Series Question? I don't know what I did wrong!

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Let $S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}$ . Then $S_k$ is the $k$ th partial sum.

$S_1$ happens to be the first term in the series, which is why that box is marked correct:

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But the next partial sum is not correct:

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and this is not the same notion as the second term (which indeed is 0.75) in the series.

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