HELP ME PLEASE I'll give brainiest

The hypotenuse of a right triangle is 10cm long. One of the triangle's legs is three times the length of the other leg. Find the

vivado [14]

Answer:

The lengths of the three sides are 10 cm, 9.49 cm and 3.16 cm

Step-by-step explanation:

Let

c ------> the length of the hypotenuse of a right triangle

x -----> the length of one leg

y -----> the length of the other leg

we know that

$c^{2}=x^{2}+y^{2}$ -----> equation A (Pythagoras Theorem)

$c=10\ cm$ ----> equation B

$x=3y$ -----> equation C

Substitute equation B and equation C in equation A and solve for y

$10^{2}=(3y)^{2}+y^{2}$

$100=10y^{2}$

$y^{2}=10$

$y=\sqrt{10}\ cm$

$y=3.16\ cm$

Find the value of x

$x=3(\sqrt{10})=9.49\ cm$

therefore

The lengths of the three sides are 10 cm, 9.49 cm and 3.16 cm

5 0

3 years ago

Read 2 more answers

take 25% off the original. now take off an additional 10% and calculate the new sales cost of this item. what is your total perc

Aneli [31]

x = original price, or 100%

if we take off 25% from 100% what's left is 75%, that's the discounted price.

let's then take 10% of that.

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{75\% of "x"}}{\left( \cfrac{75}{100} \right)x\implies 0.75x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{10\% of 0.75x}}{\left( \cfrac{10}{100} \right)0.75x\implies 0.075x}~\hfill \stackrel{\textit{total percent savings}}{0.75x-0.075x\implies 0.675x} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{changing that to percent format}}{0.675\cdot 100\implies 67.5\%}$

8 0

3 years ago

Ill give brainliest please help with this algebra!!

creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

$\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1$

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple. Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20. If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

$\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}$

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent. If it is instead a coefficient though, then this would be the answer to it.

8 0

3 years ago

Read 2 more answers

Hey guys! I’m having a lot of trouble with this paper, would anyone mind explaining one of them to me?

lyudmila [28]

Answer: See Explanation

Step-by-step explanation:

This worksheet seems to be about "Special Right Triangles"

In this worksheet, it instructs you to find the missing side lengths.

Explaining number 1)

Step 1) Identifying the triangle and what it means

Since the triangle in number one is a 45-45-90 triangle with the given side length of "1" on one of the legs of the triangle, it can be concluded that the other leg also has a side length of "1" (due to the ratio of side on a 45-45-90 degree triangle), is also states the triangle has 45 degrees labeled on one of the angles, is can also be concluded that the other missing angle is 45 degrees.

Step 2) Answer

The answer to b is 1 and the answer to a is square root of 2, due to the properties of a 45 45 90 triangle (refer attachment)

*you can also use the following attachment to help you on this problem