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Sphinxa [80]
3 years ago
5

On a coordinate plane, 2 trapezoids are shown. The first trapezoid has points A (negative 1, negative 2), B (1, negative 2), C (

2, negative 5), and D (negative 2, negative 5). The second trapezoid has points A prime (negative 4, negative 1), B prime (negative 2, negative 1), C prime (negative 1, negative 4), and D prime (negative 5, negative 4).
Which statements are true about trapezoid ABCD and its translated image, A'B'C'D'? Select two options.


The rule for the translation can be written as T–3, 1(x, y).

The rule for the translation can be written as T–1, 3(x, y).

The rule for the translation can be written as

(x, y) → (x + 1, y – 3).

The rule for the translation can be written as

(x, y) → (x – 3, y + 1).

Trapezoid ABCD has been translated 3 units to the right and 1 unit up.

ANSWER :
~ The rule for the translation can be written as T-3, 1(x, y).
~ The rule for the translation can be written as
(x, y) → (x - 3, y + 1).
Mathematics
2 answers:
Liula [17]3 years ago
9 0

Answer:

The true statements are:

The rule for the translation can be written as T-3, 1(x, y). ⇒ 1st

The rule for the translation can be written as  (x, y) → (x - 3, y + 1) ⇒ 4th

Step-by-step explanation:

Let us revise the rule of the translation:

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

The vertices of trapezoid ABCD are:

A (-1 , -2) , B (1 , -2) , C (2 , -5) , D (-2 , -5)

The vertices Of trapezoid A'B'C'D' are:

A' (-4 , -1) , B' (-2 , -1) , C' (-1 , -4) , D' (-5 , -4)

Trapezoid ABCD is translated to form Trapezoid A'B'C'D'

By using the rules of translation above:

∵ A = (-1 , -2) and A' = (-4 , -1)

- The rule of translation is (x , y) → (x + h , y + k)

∵ x = -1 and x + h = -4

∴ -1 + h = -4

- Add 1 to both sides

∴ h = -3

∵ y = -2 and y + k = -1

∴ -2 + k = -1

- Add 2 to both sides

∴ k = 1

The rule of translation is (x , y) → (x - 3 , y + 1)

The trapezoid ABCD has been translated 3 units to the left and 1 unit  up

You can check your answer by doing the same steps with the other 3 vertices you will have the same values of h and k

The true statements are:

The rule for the translation can be written as T-3, 1(x, y).

The rule for the translation can be written as  (x, y) → (x - 3, y + 1)

ValentinkaMS [17]3 years ago
4 0

Answer:

A,D

Step-by-step explanation:

I took the test on E2020.

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If so, you can solve it the hard way.

x^2 + 6x -80 = 0

(x^2 + 6x + 9) - 80 = 9

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(x+3) = 9.43

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If you're not doing those then I'm afraid your question has no answer.

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7 0
3 years ago
The length of the red line segment is 8 and the length of the blue line segment is 4. How long is the major axis of the eclipse?
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The major axis of the eclipse is 12 units long

The given parameters can be represented as:

Red = 8

Blue = 4

See attachment for illustration

To solve this question, we make use of the following theorem

The distance between a point and the foci sums up to the major axis

This translates to:

Major\ axis = Red + Blue

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7 0
3 years ago
Use your knowledge about parentheses and substitution to solve the following:
meriva

Answer:

16. r(s)(t) =

r=2, s=3, t=4

(2)(3)(4)=

             (2*3) = 6  ---> 6(4) = 24

final: 24

17. (r)(s)(t)(x)(y) =

r = 2, s = 3, t = 4, x = 5, y = 6

(2)(3)(4)(5)(6)

2*3=6

      6*4=24

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final: 720

18. (7x + 2Y) =

x = 5, y = 6

rewrite--->        = [7(5) + 2(6)]

[35 + 12] = 47

final: 47

hope this helpsss sorry took a while LOL

Step-by-step explanation:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

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