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Pie
3 years ago
12

Julie ran 32.4 miles in May and 35.8 miles in June. Greg ran the same total distance as Julie, but only ran 29.6 miles in May. H

ow far did Greg run in June?
A.
33.0 miles

B.
6.2 miles

C.
2.8 miles

D.
38.6 miles
Mathematics
1 answer:
ankoles [38]3 years ago
6 0
You take the amount of miles julie did and subtract the amount that greg did in may to get the total distance he ran in june which is 2.8
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Trudy borrowed $560.00 from a friend and agreed that for several years she would make equal monthly payments to pay only the int
likoan [24]

Answer:

$54.6

Step-by-step explanation:

Amount borrowed = $560

Interest paid in the 12-month period = 6.5% of 560 =$36.4

The amount of interest Trudy pays in 18 months is worked out as

Monthly interest = $36.4/12

Interest payable in 18 months

= ($36.4/12) x 18

= $54.6

5 0
3 years ago
Jon reads 25 pages in 30 minutes. If Jon reads 200 pages at this same rate, how long will it take him?
kupik [55]
It will take Jon 240 minutes or 4 hours.
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3 years ago
Two friends start a business. Together they spent 800 dollars for their initial inventory. They will sell all of their initial i
Paul [167]
Their selling price was 2.45 times the price they bought it. If they split the profit evenly and there was two of them, multiply their profit by two and divide that number by 800 to find how much more they sold it for, so they sold it for 245% more than they bought it
5 0
4 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
Write an expression that is equivalent to 2/3(4x + 9). (4 points) Select one: a. 8/3x + 6 b. 8/3x + 9 c. 2/3x + 6 d. 2/3x + 9
Lady_Fox [76]
You have to distribute the 2/3 across the equation.

8/3x+18/3 which is 8/3x+6 so the answer is a

I hope that helps
3 0
3 years ago
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