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3 years ago

Find the slope of a line perpendicular to the line 3x – 2y = 5.

2 answers:

7 0

The slope of this equation is 3/2 once you rearrange it into slope intercept form: y=3/2x-5/2

The slope of a line perpendicular to this equation is just opposite sign-reciprocal of the Original slope: 3/2

Change the sign to -3/2 and flip it to get -2/3

The answer is -2/3 is the slope of a line perpendicular to the equation 3x - 2y = 5

Hope this helps.

jenyasd209 [6]3 years ago

6 0

Answer:

2/3

Step-by-step explanation:

to the the slope of the perpendicular line we must first find the slope of line given in the problem. To do this we must transform this equation into the slope intercept format

The slope intercept form of a liner equation is:

Y = mx + b

Where m is slope and b is the y - intercept value.

solving the equation in the problem for y produces :

3x - 3x + 2y = -3x - 5

0 + 2y = 3x - 5

2y = - 3x - 5

2y = -3x - 5

2 2

y = - 3 x - 5

2. 2

Therefore the slope of this line is m = - 3

2

the slope of perpendicular line is the negative inverse of the slope of the line we are given,or

- 1

m

so for our problem the slope of a perpendicular line is - - 2 = 2

3. 3

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Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

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Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

8 0

3 years ago

The volume of a packing box is 5 – x cubic feet. The width of the box is x feet and the length is x – 2 feet. The height is give

photoshop1234 [79]

By definition we have that the volume is given by
V = h * w * l
where
V: Volume
h: height
w: width
l: length
Clearing the height we have:
h = V / (w * l)
h = (5 - x) / ((x) * (x - 2))
The expression is not defined for the values of x that make the denominator zero:
((x) * (x - 2)) = 0
x = 0
x = 2
Answer
h = (5 - x) / ((x) * (x - 2))
x = 0
x = 2

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3 years ago

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siniylev [52]

Answer:

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Step-by-step explanation:

Given expression:

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8 and 36 ;

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dolphi86 [110]

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Step-by-step explanation:

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Find the slope of a line perpendicular to the line 3x – 2y = 5.​

Find the slope of a line perpendicular to the line 3x – 2y = 5.