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OLga [1]
3 years ago
14

Can someone please help me with this

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0
The answer is c

Explanation: it’s c because why can’t it be c because c is just amazing and we love c
REY [17]3 years ago
3 0
Your answer is C. $1.48
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Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?
Whitepunk [10]

Given:

Point is T(-3,8).

To find:

The coordinates of T' after R(y-axis)\circ R(x-axis).

Solution:

We know that, R(y-axis)\circ R(x-axis) means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

(x,y)\to (x,-y)

T(-3,8)\to T_1(-3,-8)

If a figure reflected across y-axis, then

(x,y)\to (-x,y)

T_1(-3,-8)\to T'(-(-3),-8)

T_1(-3,-8)\to T'(3,-8)

Therefore, the required point is T'(3,-8).

4 0
3 years ago
What are the simulatities
kiruha [24]
<span>the state or fact of being similar basically saying the same

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6 0
3 years ago
Read the following poem:
pentagon [3]

Answer:

7, I believe. I have to fill in the extra character space, so I hope you have a nice day :)

6 0
3 years ago
Evaluate 12∣∣−x+3∣∣−5 when x = 11.
Evgen [1.6K]

Answer:

91

Step-by-step explanation:

12∣∣−x+3∣∣−5

Let x = 11

12∣∣−11+3∣∣−5

Do the absolute value first

12∣∣-8∣∣−5

Taking the absolute value, which means making it positive

12* 8 -5

Multiply and divide

96 -5

91

7 0
3 years ago
Please solve these questions on the topic of exponents
galina1969 [7]

Answer/Step-by-step explanation:

Recall: x^{-a} = \frac{1}{x^a}

a. 4^{-3} = \frac{1}{4^3} = \frac{1}{64}

b. 13^{-2} = \frac{1}{13^2} = \frac{1}{169}

c. (-3)^{-2} = \frac{1}{-3^2} = \frac{1}{9}

6 0
3 years ago
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