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IgorLugansk [536]
3 years ago
12

Find the missing angle measure.

Mathematics
2 answers:
EastWind [94]3 years ago
8 0
Since there are six angles, the shape is hexagon.

The sum of all the angles in a hexagon is 720°.

x° + 145° + 163° + 60° + 135° + 124° = 720°

x° + 627° = 720°

x = 720° - 627°

x = 93°

The measure of the missing angle is 93°.
sweet-ann [11.9K]3 years ago
4 0

Answer:

F = 93

Step-by-step explanation:

The angles of a hexagon should add up to 720 degrees.

Simply subtract all of the numbers and you get 93 degrees.

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Gennadij [26K]

Answer:

-24

Step-by-step explanation:

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8 0
3 years ago
Work out the value of 4° x 16°
allochka39001 [22]
64 is the answer to your question
5 0
3 years ago
Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red
GenaCL600 [577]
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



5 0
3 years ago
What is 5543×3445+211÷3??? Please help me due today!!! I will give 10 points or maybe 20pts
natka813 [3]
<span>19095705.3333  is the answer
 
hope i helped!</span>
3 0
3 years ago
Which of the following is an extraneous solution of sqrt 4x + 41 = x+5
stiv31 [10]

Answer:

x=-8

Step-by-step explanation:

\sqrt{4x+41}=x+5

on squaring both sides

4x+41=(x+5)^2\\\\4x+41=x^2+10x+25\\\\x^2+6x-16=0\\\\x^2+8x-2x-16=0\\\\x(x+8)-2(x+8)=0\\\\(x-2)(x+8)=0

either x-2=0  or  x+8=0

either x=2 or x=-8

Putting x=2 in original equation, we get

\sqrt{4\times 2+41}=2+5

7=7 hence, it is not an extraneous solution

Putting x=-8 in original equation

\sqrt{4\times (-8)+41}=-8+5

i.e. 3=-3

Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)

3 0
3 years ago
Read 2 more answers
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