Answer:
-24
Step-by-step explanation:
have a great day! feel free to mark as brainliest! :)
64 is the answer to your question
First, make a equation in which r= red and b=blue.
So, since in the first box it has 4 red models and one blue model equaling 12,
the first equation looks like 4r+b=12.
The second equation looks like 2r+b=8.
What you would do is try and first solve for r by getting rid of b.
Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.
-1*(2r+b=8)= -2r-b=-8
Add.
4r+b=12
+(-2r-b=-8)
2r=4
r=2
Then, you plug in 2 for the r for any of the original equations.
4(2)+b=12
8+b=12
b=4
or
2(2)+b=8
4+b=8
b=4
So, the red models weigh 2 pounds while the blue models weigh 4.
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Answer:
x=-8
Step-by-step explanation:

on squaring both sides

either x-2=0 or x+8=0
either x=2 or x=-8
Putting x=2 in original equation, we get

7=7 hence, it is not an extraneous solution
Putting x=-8 in original equation

i.e. 3=-3
Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)