A triangle has a perimeter of 206 inches. if the two sides of the triangle measure 59 inches and 94 inches, determined the lengt
2 answers:
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Answer:
P = 70 mi A = 210 mi^2
Step-by-step explanation:
Sides:
a = 29 m
b = 20 m
c = 21 m
Angles:
A = 90 °
B = 43.6028 °
C = 46.3972 °
Other:
P = 70 m
s = 35 m
K = 210 mi^2
r = 6 m
R = 14.5 m
Agenda:
A = angle A
B = angle B
C = angle C
a = side a
b = side b
c = side c
P = perimeter
s = semi-perimeter
K = area
r = radius of inscribed circle
R = radius of circumscribed circle
SSS is Side, Side, Side
Heron’s formula says that if a triangle ABC has sides of lengths a, b, and c opposite the respective angles, and you let the semiperimeter, s, represent half of the triangle’s perimeter, then the area of the triangle is
Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× + 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = × 100
% change in stopping distance = 7.34 %