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3 years ago

On the occasion of New year a super market announces a discount of 20

Mathematics

1 answer:

Illusion [34]3 years ago

7 0

Step - 1: Calculate 20% of 840.

$840 \times \frac {20}{100} = 168$

Step - 2: Subtract from 840.

$840-168=672$

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Answer:

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3 years ago

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Evaluate the expression please.

Tanzania [10]

Answer:

-7

Step-by-step explanation:

-3-(-10)/-2+1

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2 years ago

What is the factorization of 4x^2-8x+3

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3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago

Bess has $2.80 in quarters and dimes. The number of dimes is 7 less than the number of quarters. Find the number of quarters and

Nezavi [6.7K]

Answer:

3 dimes and 10 quarters

Step-by-step explanation:

If you add 7 dimes, then the number of dimes and quarters is the same, and the total increases to $3.50. A dime and a quarter have a value together of $0.35. Since there are equal numbers, the value $3.50 must be made up of some quantity of groups with a value of $0.35. That number of groups must be ...

... $3.50/$0.35 = 10

Thus, there are 10 quarters and 10-7 = 3 dimes.

_____

Using an equation

Let q represent the number of quarters. Then the amount Bess has is ...

... 0.10(q -7) +0.25q = 2.80

... 0.35q - 0.70 = 2.80

... 0.35q = 3.50 . . . . . add 0.70 . . . . . . . this should look familiar

... q = 3.50/0.35 = 10

4 0

3 years ago