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xxTIMURxx [149]

2 years ago

14

A circle has a radius of 7 cm. Workout the area of the circle. Give your answer correct to three significant figures.

1 answer:

anastassius [24]2 years ago

5 0

Answer:

πr²=22/7×49

=22×7

=154

hope it helps

Mark me brainliest

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Rewrite the expression in the form... (PLZ HELP QUICK I'LL GIVE BRAINLIEST)

ivanzaharov [21]

Answer: $3*z^\frac{2}{9}$

Step-by-step explanation:

The exponent 1/3 is the same thing as cube rooting the expression.

$\sqrt[3]{27\sqrt[3]{z^2} }$

3* $z^{2/9}$

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2 years ago

For questions 4-5, decide whether each table of values describes a function or not.

lara31 [8.8K]

Answer:

Function

Step-by-step explanation:

Two different X's could equal the same Y value so this is a function. Remember if there's multiple of the same input (x) equalling different outputs (y) then it is not a function. If there's multiple inputs (x) equalling the same output (y) it's just coincidence and works.

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2 years ago

What is the slope of the line y= 3?

Kipish [7]

Answer:

Undefined

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

2 years ago

138 invitations to 75 invitations,what is the percent change?

Thepotemich [5.8K]

Answer:

Convert to a decimal by dividing the numerator by the denominator.

1.84

invitations

Step-by-step explanation:

7 0

2 years ago