The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
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Absolute values of the complex numbers</h3>
The absolute values of the complex numbers are determined as follows;
(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

(-1+sqrt3i)^12 = (-1 + √3i)¹²

(sqrt 3-i)^6 = (√3 - i)⁶

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

(sqrt2-i)^6 = (√2 - i)⁶

Increasing order of the complex numbers;
(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
Learn more about complex numbers here: brainly.com/question/10662770
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Let "a number" be represented with the variable x.
Solve the expression by breaking it apart:
"...the sum of four and a number": (x + 4)
"twice of...": 2(
"Twice of the sum of four and a number": 2(x + 4)
2(x + 4) is your answer.
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I'm not sure but I think it is the first one
Answer 2019 /0.0047 /2014/ 0.493
Step-by-step explanation: