Item 10 Find the median, first quartile, third quartile, and interquartile range of the data. 38,55,61,56,46,67,59,75,65,58
jok3333 [9.3K]
I think the median is 58.5, the first quartile is 50.5, the third quartile is 66, and finally, the interquartile range is <span>12.75.</span>
A. The area of a square is given as:
<span>A = s^2 </span>
Where s is a measure of a side of a square. s = (2 x – 5)
therefore,
<span>A =
(2 x – 5)^2 </span>
Expanding,
A =
4 x^2 – 20 x + 25
<span>B.
The degree of a polynomial is the highest exponent of the variable x, in this case
2. Therefore the expression obtained in part A is of 2nd degree.</span>
Furthermore,
polynomials are classified according to the number of terms in the expression.
There are 3 terms in the expression therefore it is classified as a trinomial.
<span>C.
The closure property demonstrates that during multiplication or division, the
coefficients and power of the variables are affected while during
multiplication or division, only the coefficients are affected while the power
remain the same.</span>
L+S=8, L=8-S
500L+200S=2200, using L from above in this equation gives you:
500(8-S)+200S=2200
4000-500S+200S=2200
4000-300S=2200
-300S=-1800
S=6, and since L=8-S:
L=2
So Rita bought 2 large packets and 6 small packets.
53x2=106
250-106= 144
144/2=72
The length is 72cm
1.54 + 2.37
= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)
= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100
= 3 + 8/10 + 11/100
= 3 + 8/10 + (10/100 + 1/100)
= 3 + 8/10 + (1/10 + 1/100)
= 3 + 8/10 + 1/10 + 1/100
= 3 + 9/10 + 1/100
= 3.91
