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jekas [21]
3 years ago
8

Pls help I need to show work. Does anyone know how to do this?

Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

10.

9√256

= 9 × √256

= 9 × 16

= 144

11.

√3 × √2

= √(3 × 2)

= √6

12.

√9 × √9

= √(9 × 9)

= √81

= 9

13.

√20 × √8

= √(20 × 8)

= √160

= √(16 × 10)

= √16 × √10

= 4 × √10

= 4√10

14.

√20 × √10

= √(20 × 10)

= √200

= √(100 × 2)

= √100 × √2

= 10 × √2

= 10√2

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What is the measure of arc KL?<br><br> 20°<br> 40° <br> 48° <br> 96°
mash [69]

The question is incomplete. The complete question is here

Angle KJL measures (7x - 8)° and angle KML measures (3x + 8)°. What is the measure of arc KL, if M and J lie on the circle ?

Answer:

The measure of arc KL is 40° ⇒ 2nd answer

Step-by-step explanation:

In any circle:

  • Inscribed angles subtended by the same arc are equal
  • If the vertex of an angle lies on the circles and its two sides are chords in the circle, then it called inscribed angle
  • The measure of an inscribed angle is equal to half the measure of its subtended arc

In a Circle

∵ M lies on the circle

∵ KL is an arc in the circle

∴ MK and ML are chords in the circle

∴ ∠KML is an inscribed angle subtended by arc KL

∵ J lies on the circle

∵ KL is an arc in the circle

∴ JK and JL are chords in the circle

∴ ∠KJL is an inscribed angle subtended by arc KL

∵ Inscribed angle subtended by the same arc are equal

∴ m∠KML = m∠KJL

∵ m∠KML = (3x + 8)°

∵ m∠KJL = (7x - 8)°

- Equate them to find x

∴ 7x - 8 = 3x + 8

- Subtract 3x from both sides

∴ 4x - 8 = 8

- Add 8 to both sides

∴ 4x = 16

- Divide both sides by 4

∴ x = 4

- Substitute the value of x in the m∠KML OR KJL to find its measure

∵ m∠KML = 3(4) + 8 = 12 + 8

∴ m∠KML = 20°

∴ m∠KJL = 20°

∵ The measure of an inscribed angle is equal to half the measure

   of its subtended arc

∴ m∠KML = \frac{1}{2} (m of arc KL)

∵ m∠KML = 20°

∴ 20 = \frac{1}{2} (m of arc KL)

- Multiply both sides by 2

∴ 40° = m of arc KL

The measure of arc KL is 40°

7 0
3 years ago
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