Since we need to find the point at which the 2 lines intersect at the x-axis, we need to find where the 2nd line intersects the x axis, by plugging in y=0.
x-2(0)=4
x=4
Therefore, at (4,0).
Now we plug in (4,0) at the first equation.
4b+3(0)=10
4b=10
b=5/2
Therefore, at b=5/2
It is right it is C 454.5
Her horizontal distance to the rim satisfies the ratio
(10 ft -6 ft)/distance = tan(25°)
so the distance is
distance = (4 ft)/tan(25°) ≈ 9 ft
|2x + y - 3z|
Plug in the values
|-4 + 10 - 9|
= |-3|
= 3
<h3>
Answer: 5 < x < 29</h3>
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Explanation:
Since AB is smaller than AD, this must mean the angle ACB is smaller than angle ACD. Note how these angles are opposite the sides mentioned.
So 2x-10 < 48
At the same time, 2x-10 is also larger than 0.
Overall, we can say 0 < 2x-10 < 48
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Let's solve for x
0 < 2x-10 < 48
0+10 < 2x < 48+10 ...... add 10 to all sides
10 < 2x < 58
10/2 < x < 58/2 ..... divide all sides by 2
5 < x < 29