Answer:
The result is significant.
Step-by-step explanation:
Here,
p = 30 ÷ 330 = 0.091
thus, q = 1 - p = 0.909
Also, 
⇒ 
The z-score is:


Thus, at 95% confidence interval, p-value = 0.005
The result is significant at p < .05.
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
Given:
Arnold has $24 to spend at the movies.
Ticket = $12
Popcorn is double the price of the soda.
The soda and candy bar are same price.
To find:
The price for the soda.
Solution:
Let x be the price of soda.
According to the question,
Price of candy = Price of soda = x
Price of popcorn = 2(price of soda) = 2x
Total amount = Ticket + Popcorn + Soda + Candy




Divide both sides by 4.


Therefore, the price of soda is $3.
Given the dataset

We start by computing the average:

We compute the difference bewteen each element and the average:

We square those differences:

And take the average of those squared differences: we sum them

And we divide by the number of elements:

Finally, we take the square root of this quantity and we have the standard deviation:
