The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
<h3>What is the nth term of an arithmetic sequence?</h3>
The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
First term a1 = 
= 3/2
Last term an = 
= 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
learn more about the arithmetic sequence here:
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are , and 1/9 respectively, how many terms has the sequence?
9514 1404 393
Answer:
- vertex: (7.5, 2.25)
- f(x) = -(x -7.5)² +2.25
Step-by-step explanation:
My favorite "technology" for problems like this is the Desmos graphing calculator app or web service. It easily displays the vertex (and/or zeros) of the function.
Of course, vertex form is ...
f(x) = a(x -h)² +k . . . . . . . . vertex (h, k), leading coefficient 'a'
The solution is found by reading the graph and putting the numbers in the formula. The leading coefficient is copied from the standard form equation.
- vertex: (7.5, 2.25)
- f(x) = -(x -7.5)² +2.25
Answer:
c
Step-by-step explanation:
because it has an equal sign
Answer:
-2
Step-by-step explanation:
Answer:
It has a maximum
Step-by-step explanation:
The way I think about it is looking at "a" (the leading variable's coefficient, so __x²), if it's negative, the graph is a frown, but if it's positive, it's a smile. In this case, a is -2, so the graph would have the shape of a frown, which has a maximum.
I hope this helped!
