Answer:
188
Step-by-step explanation:
Odd integers are 1 more than even ones
even intergers are represetned as 2n where n is a whole number
odd=2n+1
consecutive odd integers are 2 apart from each other so therefor the numbers are 2n+1,2n+1+2, 2n+1+2+2 or 2n+1, 2n+3, 2n+5
so they add up to 111
2n+1+2n+3+2n+5=111
add like terms
6n+9=111
subtract 9 from both sides
6n=102
divide both sides by 6
n=17
numbers are
2n+1,2n+3,2n+5
subsitute
2(17)+1=34+1=35
therefor since the other sare 2 more
35,37,39 are the numbers
are there 3 that equal 1111? solve and see if it is true
2n+1+2n+3+2n+5=1111
add like terms
6n+9=1111
subtract 9 from both sides
6n=1102
divide both sides by 6
n=183.666666666666
n is not whole so the answer is NO
answer are 35,37,39 and NO
answer = 70
top triangle
1/2 times 5 times 5 = 12.5
12.5 times 2 = 25
bottom
14 - 5 = 9
1/2 times 5 × 9 = 22.5
22.5 times 2 = 45
45 + 25 = 70