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Bess [88]
4 years ago
11

Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and two times the firs

t is 8.
Mathematics
1 answer:
Sav [38]4 years ago
4 0

Answer:

first number= 19/5

second number= 2/5

Step-by-step explanation:

first number= a

second number= b

a+3b=5   equation 1

b+2a=8  equation 2

using equation 2 we have

b=8-2a

using equation 1 we have

a+3(8-2a)=5  

a+24-6a=5

24-5=6a-a

19=5a

a=19/5 = first number

so using b=8-2a

we have

b=8-2(19/5)

b=8-(38/5)

b=2/5 = second number

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The area rug is 4 15/32 square meters. The rug is 2 3/4 meters in length. How wide is the rug
Whitepunk [10]
Steps:
1. To do this problem, you have to divide the area by the length
2. To make this easier, turn both numbers into improper fractions
143/32 divided by 11/4
3. To divide you actually have to multiply by the reciprocal
143/32 times 4/11 equals 572/352
4. Turn 572/352 into a mixed number which is 1 220/352
5. Now you simplify it by dividing the numerator and denominator by 44
6. Your answer is.
1 5/8

6 0
4 years ago
Solve each inequality: 4p+3>9p+6-5p
slava [35]

Answer: No solution

Step-by-step explanation: when you subtract 5p from 9p you get 4p. Now you have 4p on both sides. To even it out, you have to subtract 4p from 4p. Not you are only left with the 3 and 6. The final answer is 3>6 which isn't true because 3 is LESS than 6. That is why this question has no solution.

7 0
3 years ago
A parallelogram has vertices E(-8,3), F(2,-2), G(-1,3), and H(-5, -2). What are the coordinates of the midpoint of each diagonal
IrinaVladis [17]
Use the midpoint formula

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7 0
3 years ago
Please help me with circle questions below
IRINA_888 [86]

For first question, What is approximate value of "......" this part is missing so please write whose approximate value question is asking to find

For second question we have to find tan\Theta

In right triangle ABC as show in attachment,

tan\Theta = \frac{opposite side}{adjacent side} = \frac{AB}{BC}----(1)

Now AB is given by distance of point A from x axis which will be given by its y - coordinate. So AB = \frac{1}{2}

Similarly BC is the distance of point A from y axis (horizontal distance ) and that will be given by x coordinate of A. So BC = \frac{\sqrt{3}}{2}

Plug these values in equation (1)

tan\Theta = \frac{AB}{BC} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

To divide fractions we flip (reciprocal ) bottom fraction and multiply it to top fraction as shown

tan\Theta = \frac{1}{2} \times \frac{2}{\sqrt{3}}

Now 2 in top and bottom cancels out so we are left with

tan\Theta = \frac{1}{\sqrt{3}}

so thats the final answer for tan\Theta

8 0
3 years ago
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Mars2501 [29]
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2 years ago
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